Answer:
![41\text{ [units squared]}](https://tex.z-dn.net/?f=41%5Ctext%7B%20%5Bunits%20squared%5D%7D)
Step-by-step explanation:
The octagon is irregular, meaning not all sides have equal length. However, we can break it up into other shapes to find the area.
The octagon shown in the figure is a composite figure as it's composed of other shapes. In the octagon, let's break it up into:
- 4 triangles (corners)
- 3 rectangles (one in the middle, two on top after you remove triangles)
<u>Formulas</u>:
- Area of rectangle with length
and width
:
- Area of triangle with base
and height
:
<u>Area of triangles</u>:
All four triangles we broke the octagon into are congruent. Each has a base of 2 and a height of 2.
Thus, the total area of one is 
The area of all four is then
units squared.
<u>Area of rectangles</u>:
The two smaller rectangles are also congruent. Each has a length of 3 and a width of 2. Therefore, each of them have an area of
units squared, and the both of them have a total area of
units squared.
The last rectangle has a width of 7 and a height of 3 for a total area of
units squared.
Therefore, the area of the entire octagon is ![8+12+21=\boxed{41\text{ [units squared]}}](https://tex.z-dn.net/?f=8%2B12%2B21%3D%5Cboxed%7B41%5Ctext%7B%20%5Bunits%20squared%5D%7D%7D)
Answer:
I think the answer is A.
Step-by-step explanation:
Original shape: 7 x 5 x 225 x 6 x 12 x 45 = 25,515,000
A: 9 x 5 x 225 x 6 x 35 x 12 = 25,515,000
B: 14 x 10 x 255 x 12 x 24 x 45 = 462,672,000
C: 9 x 7 x 225 x 8 x 15 x 45 = 76,545,000
D: 8 x 4 x 225 x 6 x 12 x 35 = 18,144,000
This is probably not the way you would solve it but this is how I did it. Basically I multiplied all the numbers in each shape together.
<em>(also i'm not quite sure if this is right >.< sorry!)</em>
Step-by-step explanation:
3 : x = -7.5
5 : x = -10
6 : x = 12
remaining answers are correct
Simplify
= 6/(gf^4)
hope that helps
The given expression is ![3b^2*(\sqrt[3]{54a}) + 3*(\sqrt[3]{2ab^6})](https://tex.z-dn.net/?f=%203b%5E2%2A%28%5Csqrt%5B3%5D%7B54a%7D%29%20%2B%203%2A%28%5Csqrt%5B3%5D%7B2ab%5E6%7D%29%20)
This can be simplified as :
= ![3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})](https://tex.z-dn.net/?f=%203%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B27%20%2A2%2Aa%7D%29%20%2B%203%2A%28%5Csqrt%5B3%5D%7B2%2Aa%2Ab%5E6%7D%29%20)
We know that: ![\sqrt[3]{27} = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%203%20%20%20)
Similarly we also can simplify: ![\sqrt[3]{b^6} = b^2](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7Bb%5E6%7D%20%20%3D%20b%5E2%20)
So our expression will look like this:
= ![3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%203%2A3%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20%2B%203%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
= ![9b^2*(\sqrt[3]{2a}) + 3b^2*(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%209b%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20%2B%203b%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
=![\sqrt[3]{2a}*(9b^2 + 3b^2)](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7B2a%7D%2A%289b%5E2%20%2B%203b%5E2%29%20)
=![\sqrt[3]{2a}*(12b^2)](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2a%7D%2A%2812b%5E2%29%20)
This can also be written as:
![12b^2(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%2012b%5E2%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
So the Answer is Option B