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makvit [3.9K]
4 years ago
8

A train travels at a constant speed of 35 mi/h. How long does it take the train to travel 490 mi?

Mathematics
1 answer:
allsm [11]4 years ago
7 0
14 hours . Just divide 35 into 490 & ypu get 14
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Vanyuwa [196]

Answer:

The penquins had more fish.

Number of fish polar bears and penguins had combined is 5,520.

Step-by-step explanation:

The polar bears had 2,208 fish (48 piles times 46 fish).

The penquins had 3,312 fish (144 piles [48 times 3] times 23 fish [46 divided by 2]).

2208 fish plus 3312 fish equals 5,520 fish.

4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3x%5E%7B8%7D%2A7x%5E%7B3%7D%20%7D%7B3x%5E%7B6%7D%2A7%20%7D" id="TexFormula1" title="
denis23 [38]

Answer:

a = \dfrac{x^2}{3} \quad \textsf{and} \quad b = \dfrac{x^3}{7}

Step-by-step explanation:

Given expression:

\dfrac{3x^{8} \cdot 7x^{3} }{3x^{6} \cdot 7 }

There are several ways this problem can be approached, and therefore many different answers.  The goal is to reduce the given expression to a simple product of two terms in x, set that to the given form 3a⋅7b then solve for a and b.

\implies \dfrac{3x^{8} \cdot 7x^{3} }{3x^{6} \cdot 7}

Cancel the common factors 3 and 7:

\implies \dfrac{\diagup\!\!\!\!3x^{8} \cdot \diagup\!\!\!\!7x^{3} }{\diagup\!\!\!\!3x^{6} \cdot \diagup\!\!\!\!7}

\implies \dfrac{x^8 \cdot x^3}{x^6}

Separate the fraction:

\implies \dfrac{x^8}{x^6} \cdot  x^3

\textsf{Apply the quotient rule of exponents} \quad \dfrac{a^b}{a^c}=a^{b-c}:

\implies x^{8-6} \cdot x^3

\implies x^{2} \cdot x^3

Now equate the simplified expression to the given form:

\implies x^{2} \cdot x^3=3a \cdot 7b

Therefore:

\begin{aligned}x^{2} &=3a \:\:   &\textsf{ and }\:\: \quad x^3 &=7b\\ \Rightarrow a & = \dfrac{x^2}{3} & \Rightarrow b & = \dfrac{x^3}{7}\end{aligned}

However, we could also separate them as:

\begin{aligned}x^{3} &=3a \:\:   &\textsf{ and }\:\: \quad x^2 &=7b\\ \Rightarrow a & = \dfrac{x^3}{3} & \Rightarrow b & = \dfrac{x^2}{7}\end{aligned}

Another way of writing them would be to go back a few steps and separate the fraction in x terms differently:

\implies \dfrac{x^8 \cdot x^3}{x^6}=x^8 \cdot \dfrac{x^3}{x^6}=x^8 \cdot x^{-3}

Therefore, this would give us:

\begin{aligned}x^{8} &=3a \:\:   &\textsf{ and }\:\: \quad x^{-3} &=7b\\ \Rightarrow a & = \dfrac{x^8}{3} & \Rightarrow b & = \dfrac{1}{7x^3}\end{aligned}

As the given expression reduces to x⁵, we can separate the x term in any way we like, so long as the coefficient of a is ¹/₃ and the coefficient of b is ¹/₇.  Therefore, there are many possible answers.

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