Answer:

Explanation:
Given


Each term after the second term is the average of all of the preceding terms
Required:
Explain how to solve the 2020th term
Solve the 2020th term
Solving the 2020th term of a sequence using conventional method may be a little bit difficult but in questions like this, it's not.
The very first thing to do is to solve for the third term;
The value of the third term is the value of every other term after the second term of the sequence; So, what I'll do is that I'll assign the value of the third term to the 2020th term
<em>This is proved as follows;</em>
From the question, we have that "..... each term after the second term is the average of all of the preceding terms", in other words the MEAN

<em>Assume n = 3</em>

<em>Multiply both sides by 2</em>


<em>Assume n = 4</em>


Substitute 



Assume n = 5


Substitute
and 



<em>Replace 5 with n</em>

<em>(n-1) will definitely cancel out (n-1); So, we're left with</em>

Hence,

Calculating 



Recall that 

1. <span>Find the least 3 digit dividend that would give a remainder of 4, in where the divisor is 40
=> x + 4 / 40
Since the quotient is not given, it doesn’t matter what the quotient is as long as we have a remainder of 4 when we divide it with 40
=> Let’s try multiplying 40 first to find a 3 digit number
=> 40 x 2 = 80, not the anser
=> 40 x 3 = 120, this is a 3 digit number and the least 3 digit number
Thus the equation and the answer would be
=> 120 + 4 / 40
=> 124 / 40
=> 3 remainder of 4</span>
It because it heavy rember there nothing that holds the fat