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shutvik [7]
2 years ago
10

If a data set has only 1 outlier which value will always change when the outlier is excluded

Mathematics
1 answer:
blagie [28]2 years ago
7 0

The median may stay the same.

The range will always change.

I dont think the last 2 will always change.

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Tony’s bill at the restaurant was $9.52. If he wants to leave a 20% tip, how much is that?
Ede4ka [16]

Answer: First find what 20 % of the 9.52 bill is which would be $1.90

Add $1.90 to the $9.52 = $11.42 (answer)

Step-by-step explanation:

6 0
3 years ago
Harlene tosses two number cubes. If a sum of 8 or 12 comes up, she gets 9 points. If not, she loses 2 points. What is the expect
Amanda [17]
P(8 or 12) = 1/6
P(not 8 or 12 = 5/6
Let the expected points fro one roll be X.
E(X)=9\times\frac{1}{6}-2\times\frac{5}{6}=-\frac{1}{6}\ points
The answer is -(1/6) points.
5 0
3 years ago
Read 2 more answers
What is f(g(x)) if f(x)= 4x²+3x-4 and g(x)=2x​
S_A_V [24]

Answer:

f(g(x))=16x^2+6x-4

Step-by-step explanation:

f(g(x))=4(2x)^2 +3(2x)-4

f(g(x))=16x^2+6x-4

8 0
3 years ago
What is the factorization of 729^15+1000?
igomit [66]

Answer:

The factorization of 729x^{15} +1000 is (9x^{5} +10)(81x^{10} -90x^{5} +100)

Step-by-step explanation:

This is a case of factorization by <em>sum and difference of cubes</em>, this type of factorization applies only in binomials of the form (a^{3} +b^{3} ) or (a^{3} -b^{3}). It is easy to recognize because the coefficients of the terms are <u><em>perfect cube numbers</em></u> (which means numbers that have exact cubic root, such as 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000, etc.) and the exponents of the letters a and b are multiples of three (such as 3, 6, 9, 12, 15, 18, etc.).

Let's solve the factorization of 729x^{15} +1000 by using the <em>sum and difference of cubes </em>factorization.

1.) We calculate the cubic root of each term in the equation 729x^{15} +1000, and the exponent of the letter x is divided by 3.

\sqrt[3]{729x^{15}} =9x^{5}

1000=10^{3} then \sqrt[3]{10^{3}} =10

So, we got that

729x^{15} +1000=(9x^{5})^{3} + (10)^{3} which has the form of (a^{3} +b^{3} ) which means is a <em>sum of cubes.</em>

<em>Sum of cubes</em>

(a^{3} +b^{3} )=(a+b)(a^{2} -ab+b^{2})

with a= 9x^{5} y b=10

2.) Solving the sum of cubes.

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)((9x^{5})^{2}-(9x^{5})(10)+10^{2} )

(9x^{5})^{3} + (10)^{3}=(9x^{5} +10)(81x^{10}-90x^{5}+100)

.

8 0
2 years ago
Help! Select all of the potential solution(s) of the equation 2log5x = log54.
Nastasia [14]

Answer:

  • x = 2

Step-by-step explanation:

  • 2 log₅ x = log₅ 4
  • 2 log₅ x = log₅ 2²
  • 2 log₅ x = 2 log₅ 2
  • log₅ x = log₅ 2
  • x = 2
7 0
3 years ago
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