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3 years ago

6

WILL MARK BRAINLIEST!!!! PLZ HELP!!!! Using the two-way table, what percentage of the students that like to travel out of state

do not like camping? Round to the nearest whole percent.

1 answer:

grigory [225]3 years ago

7 0

Answer:

41%

Step-by-step explanation:

The table shows that 36 of the 88 students that like traveling out of state do not like camping. That percentage is ...

36/88 × 100% ≈ 41%

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Use the drawing tools to form the correct answer on the provided graph. Graph the solution to the following linear inequality in

JulsSmile [24]

Answer:

solve for x first and then y

Step-by-step explanation:

once you know what x is than y , ur answer will equall out

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3 years ago

08 Match the following

nataly862011 [7]

English. ???????????

8 0

3 years ago

A2 = -8 and a5 = -512<br> Find a10

yawa3891 [41]

Answer:

The value of a₁₀ is -1352

Step-by-step explanation:

a₂ = -8

a₅ = -512

Now,

a₂ = -8 can be written as

a + d = -8 ...(1) and

a₅ = -512 can be written as

a + 4d = -512 ...(2)

Now, from equation (2) we get,

a + 4d = - 512

a + d + 3d = - 512

(-8) + 3d = - 512 (.°. <u>a + d = </u><u>-8</u><u>)</u>

3d = - 512 + 8

3d = - 504

d = - 504 ÷ 3

d = - 168

Now, for the value of a put the value of d = -168 in equation (1)

a + d = -8

a + (-168) = -8

a - 168 = -8

a = 168 - 8

a = 160

Now, For a₁₀

a₁₀ = a + 9d

a₁₀ = 160 + 9(-168)

a₁₀ = 160 - 1512

a₁₀ = -1352

Thus, The value of a₁₀ is -1352

<u>-TheUnknownScientist</u>

8 0

3 years ago

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$

8 0

3 years ago

Please help meeeee :,(

Crank

Answer:

I pretty sure the answer is <u>A</u><u>S</u><u>A</u>, I hope it's right!

6 0

3 years ago