Answer:
Step-by-step explanation:
Answer:
Answer in explanation.
Step-by-step explanation:
Lets take

as L1.
Take L2 the line perpendicular to L1.
Standard form of equation of line:
y=mx+c, where m = slope and c = y-intercept.
Since L1 and L2 are perpendicular,
mL1 x mL2 = -1
Substitute mL1 into the equation,
3/4 x mL2 = -1
mL2 = -1 ÷ 3/4
mL2 = -4/3
L2 : y = mx+ c
Substitute y = 6, x = 8 and m = -4/3 into the equation,

therefore L2:

Lets take L3 as the line parallel to L1.
Since L3 and L1 are parallel,
mL3 = mL1 = 3/4
equation of line: y = mx+c
substitute y = 6, x = 8 and m = 3/4 into equation.

therefore L3:

Answer:
y = 4x + 6
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = 4, thus
y = 4x + c ← is the partial equation
To find c substitute (- 1, 2) into the partial equation
2 = - 4 + c ⇒ c = 2 + 4 = 6
y = 4x + 6 ← equation of line
Answer:
29
Step-by-step explanation:
firat 4 78374748383838
Answer:
Step-by-step explanation:
We have given that:
There are 20 alligators in the swamp. Each year, the number of alligators increases by 25%. There are 25 crocodiles in the swamp. Each year, 10 new crocodiles join the swamp
Part A:
According to the above mentioned statement the function for representing the number of alligators and crocodiles in the swap throughout the year is:
Alligators = y=20(1.25)^x (x represents years)
crocodiles: y=10x+25
Part B:
Number of alligators after 4 years in the swap = y=20(1.25)^x
Number of alligators after 4 years in the swap = y=20(1.25)^4
Number of alligators after 4 years in the swap=48.82
This shows that about 48 to 49 alligators will be there in the swap after 4 year
Number of crocodiles after 4 years in the swap = y= 10(4)+25 = 65
Part C:
We will use the graph method to solve this part:
After approximately 7 years, the number of animals of each type will be the same, 95.