Question

Let the sample space be upper s equals startset 1 comma 2 comma 3 comma 4 comma 5 comma 6 comma 7 comma 8 comma 9 comma 10 endset. suppose the outcomes are equally likely. compute the probability of the event eequals​"an odd number less than 9​."

Answer 1

That looks like the natural numbers 1 through 10, so ten of them.  An odd number less than nine is 1,3,5,7, four of them.  If they're equally likely, our probability is

$p = \dfrac 4 {10} = \dfrac 2 5$

Answer 2

$|\Omega|=10\\ |A|=4\\\\ P(A)=\dfrac{4}{10}=\dfrac{2}{5}=40\%$