Ask question

Ask question

All categories

3 years ago

9

A rectangle was rearranged to form a parallelogram. How is the height of the parallelogram similar to and different from the wid

th of the rectangle?

1 answer:

Daniel [21]3 years ago

5 0

A parallelogram is just a rectangle with the sides angled, it’s pretty much the same as a rectangle and all your working out should be the same as a rectangle

You might be interested in

A delivery truck is transporting boxes of two size: the combined weight of a large box and a small box is 65 pounds. The truck i

Bas_tet [7]

pretty much about the same as before.

a = weight of a large box

b = weight of a small box.

we know their combined weight is 65 lbs, thus a + b = 65.

we also know that the truck has 60 large ones, and 55 small ones, thus 60*a is the total weight for the large ones and 55*b is the total weight for the small ones, and we know that is a total of 3775, 60a + 55b = 3775.

$\bf \begin{cases} a+b=65\\ \boxed{b}=65-a\\ \cline{1-1} 60a+55b=3775 \end{cases}\qquad \qquad \stackrel{\textit{substituting on the 2nd equation}}{60a+55\left( \boxed{65-a} \right)=3775} \\\\\\ 60a+3575-55a=3775\implies 5a+3575=3775\implies 5a=200 \\\\\\ a=\cfrac{200}{5}\implies \blacktriangleright a = 40 \blacktriangleleft \\\\\\ \stackrel{\textit{since we know that}}{b=65-a\implies }b=65-40\implies \blacktriangleright b=25\blacktriangleleft$

6 0

4 years ago

The stream of water from a fountain follows a parabolic path. The stream reaches a maximum height of 7 feet, represented by a ve

xenn [34]

First of all, I'm going to assume that we have a concave down parabola, because the stream of water is subjected to gravity.

If we need the vertex to be at $x=4$ , the equation will contain a $(x-4)^2$ term.

If we start with $y=-(x-4)^2$ we have a parabola, concave down, with vertex at $x=4$ and a maximum of 0.

So, if we add 7, we will translate the function vertically up 7 units, so that the new maximum will be $(4, 7)$

We have

$y = -(x-4)+7$

Now we only have to fix the fact that this parabola doesn't land at $(8,0)$ , because our parabola is too "narrow". We can work on that by multiplying the squared parenthesis by a certain coefficient: we want

$y = a(x-4)^2+7$

such that:

$a$
when we plug $x=8$ , we have $y=0$

Plugging these values gets us

$0 = a(8-4)^2+7 \iff 16a+7=0 \iff a = -\dfrac{7}{16}$

As you can see in the attached figure, the parabola we get satisfies all the requests.

3 0

3 years ago

According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?

scoundrel [369]

we have

$f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3$

we know that

<u>The Rational Root Theorem</u> states that when a root 'x' is written as a fraction in lowest terms

$x=\frac{p}{q}$

p is an integer factor of the constant term, and q is an integer factor of the coefficient of the first monomial.

So

in this problem

the constant term is equal to $3$

and the first monomial is equal to $15x^{11}$ -----> coefficient is $15$

So

possible values of p are $1, and\ 3$

possible values of q are $1, 3, 5, and\ 15$

therefore

<u>the answer is</u>

The all potential rational roots of f(x) are

(+/-) $\frac{1}{15}$ ,(+/-) $\frac{1}{5}$ ,(+/-) $\frac{1}{3}$ ,(+/-) $\frac{3}{5}$ ,(+/-) $1$ ,(+/-) $3$

3 0

3 years ago

Read 2 more answers

What is 96/104 in simplest form

Alecsey [184]

12/13 I believe :) hope it helps

8 0

3 years ago

Read 2 more answers

2x (3x5) - (8-3)= what is the answer please

bekas [8.4K]

Answer:

2x15-5=30-5=25 So, the answer is 25.

6 0

3 years ago