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Olegator [25]
3 years ago
7

What is 96/104 in simplest form

Mathematics
2 answers:
Alecsey [184]3 years ago
8 0
12/13 I believe :) hope it helps

Nutka1998 [239]3 years ago
4 0
12/13. You have to find the greatest common denominator. Then you simplifed it till it can't be simplified no more
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Which of the following is a correct equation for the line passing through the
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Answer:

C

Step-by-step explanation:

m = -3

y = mx +b

y = -3x + b

Plugin x = -1 and y = 4

4 = -3*(-1) +b

4 = 3 + b

4-3 = b

b = 1

y = -3x + 1

6 0
2 years ago
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All students = 700
Sedaia [141]

Answer:

  • See below

Step-by-step explanation:

<u>Given:</u>

  • Total number = 700
  • Off grid class = 450
  • Online class = 320
  • Both = 275

<u>Based on the given we find the following</u>

1) <u>Off-grid class only:</u>

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3) <u>Online class only:</u>

  • 320 - 275 = 45

2) <u>None of the classes:</u>

  • 700 - (175 + 275 + 45) = 205

4) <u>Not online:</u>

  • 700 - 320 = 380

5) <u>Not off-grid:</u>

  • 700 - 450 = 250
7 0
2 years ago
How to find an unknown angle in a quadrilateral
cricket20 [7]
Subtract the sum of the angles from 180 degrees to get the missing angle. For example if a triangle in a quadrilateral had the angles of 30 and 50 degrees, you would have a third angle equal to 100 degrees (180 - 80 = 100).
4 0
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1.<br> Which transformation takes shape Sonto shape M?
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2 years ago
The number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.
Alchen [17]

Answer:

Probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is 0.89435.

Step-by-step explanation:

We are given that the number of hours spent per week on household chores by all adults has a mean of 28 hours and a standard deviation of 7 hours.

Also, sample of 49 adults is given.

<em>Let X = number of hours spent per week on household chores</em>

So, assuming data follows normal distribution; X ~ N(\mu=28,\sigma^{2}=7^{2})

The z score probability distribution for sample mean is given by;

               Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = mean hours = 28

            \sigma = standard deviation = 7 hours

            n = sample of adults = 49

<em>Let </em>\bar X<em> = sample mean hours spent per week on household chores</em>

So, probability that the mean hours spent per week on household chores by a sample of 49 adults will be more than 26.75 is given by =P(\bar X > 26.75 hours)

    P(\bar X > 26.75 hours) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{26.75-28}{\frac{7}{\sqrt{49} } } ) = P(Z > -1.25) = P(Z < 1.25)

                                                                     = 0.89435  {using z table}

Therefore, probability that the mean hours spent per week on household chores is more than 26.75 is 0.89435.

4 0
2 years ago
Read 2 more answers
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