All categories

3 years ago

3y+2+3x-y+5x i need help doing combine like terms

Mathematics

2 answers:

sweet-ann [11.9K]3 years ago

6 0

Answer:

8x+2y+2

Step-by-step explanation:

First, write it out as it's given:

3y+2+3x-y+5x

Then, combine the x-terms first:

3y+2-y+8x

Next, combine the y-terms:

2+2y+8x

Natasha2012 [34]3 years ago

3 0

Answer:

8x+2y+2

Step-by-step explanation:

You might be interested in

Petra jogs 5 miles in 40 minutes. At this rate, how long would it take her to jog 7 miles?

Wittaler [7]

(40 min)/(5 mi) = (time)/(7 mi) . . . . . the rates are the same
(7/5)*(40 min) = time = 56 min

At the same rate, it would take Petra 56 minutes to jog 7 miles.

6 0

3 years ago

Read 2 more answers

Find the term to term rules for the following sequences:<br> 2, 6, 18, 54, 162

ki77a [65]

The term rules for the following sequences is that you multiply each number by 3! Hope this helps and please mark brainliest :)

6 0

3 years ago

Read 2 more answers

Identify the y-intercept of the exponential<br> function.

LekaFEV [45]

(0,1) is the correct answer :)

6 0

3 years ago

Find the difference between8/15 and 2/3 Show all calculations in your final answer.

kherson [118]

Answer:

$\frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}$

Step-by-step explanation:

Let the value of a number 'a' be = 8/15

Let the value of a number 'b' be = 2/3

The difference between the two numbers can be calculated by subtracting the numbers

$a-b=\frac{8}{15}-\left(\frac{-2}{3}\right)$

$\mathrm{Remove\:parentheses}:\quad \left(a\right)=a$

$=\frac{8}{15}-\frac{-2}{3}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b}$

$=\frac{8}{15}-\left(-\frac{2}{3}\right)$

$\mathrm{Apply\:rule}\:-\left(-a\right)=a$

$=\frac{8}{15}+\frac{2}{3}$

$\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}$

$=\frac{8+10}{15}$

$=\frac{18}{15}$

$\mathrm{Cancel\:the\:common\:factor:}\:3$

$=\frac{6}{5}$

Thus,

$\frac{8}{15}-\left(\frac{-2}{3}\right)=\frac{6}{5}$

3 0

3 years ago

In circle E, AC=4, CG=6, and AH=3, Find HB and EG. If necessary, round to the tenths place.

bezimeni [28]

Using theorem about secant segments we can write,
AB*AH=AG*AC
AC=4,
CG=6
AG=AC+CG=4+6=10
AH=3
AB= AH+HB=AH+x=3+x
(3+x)*3=10*4
9+3x=40
3x=40-9
3x=31
x=31/3≈10.3
HB≈10.3
EG=HB/2 (as radius and diameter)
EG=10.3/2≈5.2

3 0

3 years ago