All categories

3 years ago

Can’t figure this out could you help me ?

Mathematics

1 answer:

Rasek [7]3 years ago

3 0

Answer: - 1 1/4

Step-by-step explanation:

-6/4 as a mixed number is - 1 1/2, also known as -1 2/4. The nearest numbers to this number are -1 1/4 and -1 3/4. Since the question asks for the number one tick mark to the right, it is - 1 1/4. Since the negative number goes like -3, -2 -1, 0.

You might be interested in

Solve(x+y)^2=(x^2-2xy+y^2) and show your work

Shtirlitz [24]

(x + y)^2 = (x^2 - 2xy + y^2)

First distribute the ^2 on the left side of the equation to each term inside the parenthesis:

x^2+ 2xy + y^2

Now pick one of the variables to solve for and isolate it:

(solving for x)

x^2 + 2xy + y^2 = x^2 - 2xy + y^2

x^2+ 2xy = x^2 - 2xy

2xy = -2xy

-x = x

x = 0

When you solve for y in the equation it will turn out to be 0 as well

7 0

3 years ago

Read 2 more answers

How many congruent sides are on a Right Isosceles Triangle?

disa [49]

Answer:

I think it's 2.

3 0

2 years ago

What is the quotient of 25÷6

timama [110]

25 is the quotient I think haven't done this in 5 years

7 0

2 years ago

Read 2 more answers

If I flip a coin 200 times and it lands heads of every time what is the probability that it will land a heads up on the next fli

jeyben [28]

Answer: The answer is still 50/50

Step-by-step explanation:

because there is 2 sides of a coin ( heads, and tails ) no matter how many times you flip it, the chances will forever stay at 50/50

4 0

2 years ago

Read 2 more answers

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.

$h^-^1\ o\ h$

$\frac{(3x+4)-4}{3}\\\\=\frac{3x+4-4}{3}\\\\=\frac{3x}{3}\\\\=x$

Now substitute (-3) in place of (x),

$=-3$

8 0

2 years ago