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lys-0071 [83]
3 years ago
12

These triangles could be proven congruent by ASA. True or False.

Mathematics
2 answers:
RSB [31]3 years ago
7 0
True they could be congruent by ASA
zlopas [31]3 years ago
3 0
True..................
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Which equation is equivalent to
rosijanka [135]

Answer:

3 and 2 r equivalent i belive

5 0
2 years ago
What number divided by 2 3 4 5 6 has a remainder of 1 but when divided by 7 has no remainder?
Afina-wow [57]
301

We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...

However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.

Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7). 

301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.

Hope this all makes sense.
3 0
3 years ago
A rectangle is placed around a semicircle as shown below. The length of the rectangle is 14mm. Find the area of the shaded regio
Damm [24]

Image is missing, so i have attached it

Answer:

21.07 mm²

Step-by-step explanation:

We will use the Formulas:

Area of semicircle = πr²/2

Area_rectangle = Length x width = Lw

We are given:

Length of rectangle = 14 mm

From the attached image, the diameter of the semicircle is equal to the length of the rectangle.

Thus;

diameter of semicircle = length of rectangle

Therefore,

diameter of semicircle = 14 mm

Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.

Thus;

diameter of semicircle/2 = radius of semicircle

Hence;

radius of semicircle = 14/2 = 7mm = width of rectangle

Thus;

Area of rectangle = L*w = 14 × 7 = 98 mm²

Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²

To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.

Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²

7 0
3 years ago
There are 30 students in Mr. Hollands music class of 30 percent of the students play in the school band how many students in the
Alisiya [41]
Of means multiply. 
30%=0.3

30*0.3=9

9 students play in the school band
3 0
3 years ago
Whatcha statements describes the graph of the system of equations
ch4aika [34]

Answer:

Lines are parallel

Step-by-step explanation:

6 0
3 years ago
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