Answer:
3 and 2 r equivalent i belive
301
We could start by finding the lowest common multiple of 2, 3, 4, 5, and 6, which is 60. Then, we can consider the next few multiples: 120, 180, 240, 300...
However, because we need a remainder of 1 when our number is divided by each of these numbers (2,3,4,5,6), we want to go one above each of these multiples. So we're talking about 61, 121, 181, 241, 301... Those are the numbers that will satisfy the "remainder of 1" part of the question.
Now, we need to find out which one satisfies the other part of the question, which just requires dividing each of these numbers by 7 to see which is divisible by 7 (in other words, which one gives us a remainder of zero when we divide by 7).
301 does it. 301/7 = 43. So 301 is a multiple of 7 and therefore will yield no remainder when divided by 7.
Hope this all makes sense.
Image is missing, so i have attached it
Answer:
21.07 mm²
Step-by-step explanation:
We will use the Formulas:
Area of semicircle = πr²/2
Area_rectangle = Length x width = Lw
We are given:
Length of rectangle = 14 mm
From the attached image, the diameter of the semicircle is equal to the length of the rectangle.
Thus;
diameter of semicircle = length of rectangle
Therefore,
diameter of semicircle = 14 mm
Also, from the attached image, the radius of the semicircle is equal to the width of the rectangle.
Thus;
diameter of semicircle/2 = radius of semicircle
Hence;
radius of semicircle = 14/2 = 7mm = width of rectangle
Thus;
Area of rectangle = L*w = 14 × 7 = 98 mm²
Area of semicircle = πr²/2 = π×7²/2 = 76.93 mm²
To get the area of the shaded region, we will subtract area of the semi-circle from the area of the rectangle.
Area of shaded region = Area_rectangle - Area_semicircle = 98 - 76.93 = 21.07 mm²
Of means multiply.
30%=0.3
30*0.3=9
9 students play in the school band
Answer:
Lines are parallel
Step-by-step explanation: