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lys-0071 [83]
3 years ago
12

These triangles could be proven congruent by ASA. True or False.

Mathematics
2 answers:
RSB [31]3 years ago
7 0
True they could be congruent by ASA
zlopas [31]3 years ago
3 0
True..................
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A parks and recreational board in Birch County is interested in estimating the proportion of its residents in favor of having mo
ankoles [38]

Answer:

B.

Step-by-step explanation:

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I just did it.

5 0
3 years ago
Which is an equivalent form of the expression 1800(1.2)^-t
ololo11 [35]

Answer:

1800(5/6)^t

Step-by-step explanation:

I don't see any answer choices, but this would be another form if it is listed. The negative exponent means that you get the reciprocal of the fraction (in this case 1.2). This turns 1.2 into (1/1.2), which is equivalent to 5/6.

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1 year ago
Which number represents the country of Egypt <br> A) 1 <br> B) 2<br> C) 3<br> D) 4
valkas [14]

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3 years ago
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Which of the following is a solution of x2 + 2x + 8?
zubka84 [21]
Using the quadratic equation we get:
\frac{ - 2 + - \sqrt{4 - 32} }{2} = \frac{ - 2 + - \sqrt{ - 28} }{2}

Factoring out 2 we get
\frac{ - 2 + - 2\sqrt{ - 7} }{2} = - 1( + - ) \sqrt{ - 7}
Factoring out the imaginary number:
- 1 + \sqrt{7} i \: (and) \: - 1 - \sqrt{7} i
So b.
4 0
2 years ago
(a) The parametric equations x = f(t) and y = g(t) give the coordinates of a point (x, y) = (f(t), g(t)) for appropriate values
Gnesinka [82]

Answer:

Step-by-step explanation:

a). Given a parametric equation, we are describing a set of coordinates based on the value of t. The variable t is called the parameter.

b) we have the following equations. x=t y=t^2, so in order for us to know where the object is at t=t' we must replace t with the specific value t'. Hence, when t=0 the object is at (0,0^2) = (0,0) (the origin). When t=6, the object is at (6,6^2) = (6,36).

c). To eliminate the parameter, we replace the parameter in one equation by using the second equation. Recall that we have that x=t. Then, by replacing in the second equation, we have the following

y=t^2 = (x)^2 = x^2

where x\geq 0

5 0
2 years ago
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