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3 years ago

What is the surface area of a cube that measures 5 inches on each side?

Mathematics

1 answer:

Kryger [21]3 years ago

5 0

Answer:

150 in²

Step-by-step explanation:

5 x 5 x 6 = 150

surface area of cube is 6 times (6 congruent faces) of one face. 5 x 5 = 25

25 x 6 = 150

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astraxan [27]

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3 years ago

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Multiply and simplify 8 times 3/10

ad-work [718]

Answer:

2.4 Hope this helped

Step-by-step explanation:

8/1 x 3/10

24/10

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What is the point-slope form of the equation of a line that passes through the point (1, 4) and has a slope of −3?

insens350 [35]

I hope this helps you

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3 years ago

Write each expression as an algebraic (nontrigonometric) expression in u, u > 0.

max2010maxim [7]

Answer:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

Step-by-step explanation:

We want to write the trignometric expression:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0$

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

$\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)$

Take the secant of both sides:

$\displaystyle \sec(\theta)=\frac{u}{10}$

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

$\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}$

By substitutition:

$\displaystyle= \sin(2\theta)$

Using an double-angle identity:

$=2\sin(\theta)\cos(\theta)$

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

$\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)$

Simplify. Therefore:

$\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0$

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2 years ago

Please answer i really wanna pass (;´༎ຶٹ༎ຶ`)

motikmotik

The answer is 2/3 shirt per hour.

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3 years ago

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