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Yakvenalex [24]
3 years ago
6

1/2(3g-2)=g/2 what is the answer?

Mathematics
1 answer:
Deffense [45]3 years ago
7 0
1/2(3g - 2) = g/2....multiply the entire equation by 2
3g - 2 = g
-2 = g - 3g
-2 = -2g
-2/-2 = g
1 = g
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Let Y be a random variable with a density function given by
Neporo4naja [7]

From the given density function we find the distribution function,

F_Y(y)=P(Y\le y)=\displaystyle\int_{-\infty}^y f_Y(t)\,\mathrm dt=\begin{cases}0&\text{for }y

(a)

F_{U_1}(u_1)=P(U_1\le u_1)=P(3Y\le u_1)=P\left(Y\le\dfrac{u_1}3\right)=F_Y\left(\dfrac{u_1}3\right)

\implies F_{U_1}(u_1)=\begin{cases}0&\text{for }u_1

\implies f_{U_1}(u_1)=\begin{cases}\frac{{u_1}^2}{18}&\text{for }-3\le u_1\le3\\0&\text{otherwise}\end{cases}

(b)

F_{U_2}(u_2)=P(3-Y\le u_2)=P(Y\ge3-u_2)=1-P(Y

\implies F_{U_2}(u_2)=\begin{cases}0&\text{for }u_2

\implies f_{U_2}(u_2)=\begin{cases}\frac32(u_2-3)^2&\text{for }2\le u_2\le4\\0&\text{otherwise}\end{cases}

(c)

F_{U_3}(u_3)=P(Y^2\le u_3)=P(-\sqrt{u_3}\le Y\le\sqrt{u_3})=F_Y(\sqrt{u_3})-F_y(\sqrt{u_3})

\implies F_{U_3}(u_3)=\begin{cases}0&\text{for }u_3

\implies f_{U_3}(u_3}=\begin{cases}\frac32\sqrt u&\text{for }0\le u\le1\\0&\text{otherwise}\end{cases}

5 0
3 years ago
If bob earns 35,000 a month how much does he earn in 2 years and 75 weeks
nlexa [21]
Okay, do 35,000x24=840,000
840,000/104=8,077
8077x75=605,769
605,769+840,000=1,445,769.23
:-)
6 0
3 years ago
Read 2 more answers
In the diagram the measure of angle 3 is 105 degrees which angle must also measure 105 degrees?
valentina_108 [34]

Answer: C

Step-by-step explanation:

I am sorry if I don't correct

7 0
3 years ago
Please help!
r-ruslan [8.4K]

Answer:

number less than 3=1 and 2

so 2/6 = 1/3 in lowest terms

then rolling a 6 =

there is only one 6 so it will be 1/6

I hope I helped

7 0
2 years ago
Pat needs to paint an 8 ft x 36 ft rectangular wall. what is the area that she paints?
lora16 [44]

area = L x W

area = 8 x 36

area = 288 square feet

5 0
3 years ago
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