3x + (x-2) =10
4x-2=10
4x=12
x=3
y=3-2=1
Answer is D
You can rewrite your function as
![f(x) = x^3(ax^3+bx+c)](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E3%28ax%5E3%2Bbx%2Bc%29)
This implies that
![f(x)=0 \iff x^3=0\quad\lor\quad ax^3+bx+c=0](https://tex.z-dn.net/?f=f%28x%29%3D0%20%5Ciff%20x%5E3%3D0%5Cquad%5Clor%5Cquad%20ax%5E3%2Bbx%2Bc%3D0)
Now, we have
, so it counts as a solution.
On the other hand, depending on the coefficient a, b and c, the cubic equation
![ax^2+bx+c=0](https://tex.z-dn.net/?f=ax%5E2%2Bbx%2Bc%3D0)
can have either one or three solutions.
So, we have the solution x=0, and then one or three solutions coming from the cubic part. The equation as a whole thus have either two or four solutions, depending on the coefficients.
Answer:
x = 1
, y = 3
Step-by-step explanation:
y = -2x + 6 --- Equation 1
y = 4x - 1 --- Equation 2
Since both (-2x + 6) and (4x - 1) have the same total, y, they are equal.
-2x + 6 = 4x - 1
Isolate the like terms.
6 + 1 = 4x + 2x
Evaluate like terms.
6x = 7
Find x.
x = ![\frac{7}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B7%7D%7B6%7D)
x = 1
Substitute x =
into Equation 2:
y = 4x - 1
y = 4(
) - 1
= 4
- 1
y = 3
B. 11+11=10+12
11+11 is 22
And 10+12 is 22
So the statement is true because both sides are equal
Answer:
6x^2 -31x +40
Step-by-step explanation:
2x * 3x + 2x * - 8 + -5 * 3x -5 * -8 Distributive property
6x^2 -16x -15x + 40 Math
6x^2 -31x +40 Answer