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sasho [114]
3 years ago
8

Sebastian studies from 3:15 - 4:45 p.m his sister,Sara studies from 4:30 -6:15 p.m who studies longer and by how,much?

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
5 0

Answer:

Sara studies longer by 15 minutes.

Step-by-step explanation:

Let's calculate how long Sebastian studies for. From 3:15 - 4:15, there is 1 hour and from 4:15 to 4:45, there are 30 minutes so Sebastian studies for 1 hour and 30 minutes. Now, let's calculate how long Sara studies for. From 4:30 - 5:30, there is 1 hour, from 5:30 - 6:00, there are 30 minutes and from 6:00 - 6:15, there are 15 minutes so Sara studies for 1 hour 45 minutes. This means that Sara studies longer by 45 - 30 = 15 minutes.

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1. Consider the figure below where ZV is parallel to WY.
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Part A:

m∠VHT = 152°

Part B:

m∠QTS = 152°

Part C:

m∠ZHQ = 28°.

Step-by-step explanation:

Part A:

The given parameters are;

m∠HXU = 113°

Segment BQ and segment UD intersect at m∠XAT = 95°

We have that m∠HXU + m∠HXS = 180° (Angles on a straight line)

Therefore;

m∠HXU  = 180° - m∠HXS = 180° - 113° = 67°

m∠HXU = 67°

m∠XAT + m∠XAH = 180° (Angles on a straight line)

m∠XAH  = 180° - m∠XAT = 180° - 95° = 85°

m∠XAH = 85°

In triangle XAH, we have;

m∠XAH + m∠HXU + m∠XHA = 180° (Angle sum property of a triangle)

∴ m∠XHA = 180° - (m∠XAH + m∠HXU) = 180° - (85° + 67°) = 28°

m∠XHA = 28°

m∠VHT + m∠XHA = 180° (Angles on a straight line)

m∠VHT  = 180° - m∠XHA = 180° - 28° = 152°

m∠VHT = 152°

Part B:

m∠QTS ≅ m∠VHT (Corresponding angles are congruent)

∴ m∠QTS = 152° (Substitution property)

Part C:

m∠ZHQ ≅ m∠XHA  (Reflexive property)

∴ m∠ZHQ = 28°.

3 0
3 years ago
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