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rusak2 [61]
3 years ago
9

What is the derivative of secx

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0
D/dx sec x=d/dx 1/cos x= sec x tan x
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A student is assessing the correlation between the number of workers in a factory and the number of units of output produced dai
miskamm [114]

Answer:

15

Step-by-step explanation:

Plug the number into the equations

3 0
3 years ago
The half-life of a certain radioactive element is 35 hours. If there are 904 grams of this element, how much will be left after
Cloud [144]
<h3>Answer: 226 grams</h3>

===========================================================

Explanation:

The half-life is 35 hours. This means every 35 hours, the amount of the substance is cut in half. If we started with 100 grams, then 35 hours later, we will have 50 grams. Then another 35 hours later we will then have 25 grams, and so on.

In this case, we start with 904 grams and follow this sequence:

904, 452, 226, 113, ...

Each term is cut in half. Going from term to term it takes 35 hours each. The third term 226 is the result of waiting two half-lives, which is 2*35 = 70 hours that have elapsed total.

--------------

If you want to use a formula, then it would be

y = A*\left(\frac{1}{2}\right)^{x/H}

where,

H = half-life duration (in this case, it is 35)

A = starting amount (which is 904 in this case)

x = amount of time that has elapsed (we will plug in x = 70)

y = final amount after x units of time has elapsed

note that x and H must have the same time unit. Both are in terms of hours in this case.

------------

So we will plug A = 904, x = 70, H = 35 into the formula to get...

y = A*\left(\frac{1}{2}\right)^{x/H}\\\\y = 904*\left(\frac{1}{2}\right)^{70/35}\\\\y = 904*(0.5)^{2}\\\\y = 904*(0.25)\\\\y = 226\\\\

We see that x = 70 leads to y = 226. This means after 70 hours, there is 226 grams of the material left.

4 0
3 years ago
Solve for x. PLease Help right now.
Leni [432]

Answer: 9

Step-by-step explanation: The smaller triangle is half the size of the bigger one so the answer would just be half of 18

7 0
4 years ago
Read 2 more answers
Use elimination but HURRY
bija089 [108]

Answer:

The solution of the system is the point (-2,4)

Step-by-step explanation:

we have

2x-\frac{3}{4}y=-7 ---> equation A

x+\frac{1}{2}y=0 ----> equation B

Solve the system by elimination

Multiply the equation B by -2 both sides

-2(x+\frac{1}{2}y)=-2(0)

-2x-y=0 ----> equation C

Adds equation A and equation C

2x-\frac{3}{4}y=-7\\-2x-y=0\\--------\\\\-\frac{3}{4}y-y=-7\\\\-\frac{7}{4}y=-7\\\\y=4

<em>Find the value of x</em>

substitute the value of y in any equation

x+\frac{1}{2}(4)=0

x+2=0

x=-2

The solution of the system is the point (-2,4)

8 0
3 years ago
Which of these correct?
garri49 [273]
I'm guessing it would be (a.) 
Hope this helps. :D
4 0
3 years ago
Read 2 more answers
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