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xxTIMURxx [149]
2 years ago
10

52.85 - 9.09 = what rounded to the nearest one

Mathematics
1 answer:
bonufazy [111]2 years ago
6 0
52.85 - 9.09 rounded to the nearest one is 44
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A random sample of 625 10-ounce cans of fruit nectar is drawn from among all cans produced in a run. Prior experience has shown
diamong [38]

Answer:

10.57% probability that the mean contents of the 625 sample cans is less than 9.995 ounces.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 10, \sigma = 0.1, n = 625, s = \frac{0.1}{\sqrt{625}} = 0.004

What is the probability that the mean contents of the 625 sample cans is less than 9.995 ounces?

This is the pvalue of Z when X = 9.995. So

Z = \frac{X - \mu}{s}

Z = \frac{9.995 - 10}{0.004}

Z = -1.25

Z = -1.25 has a pvalue of 0.1057

So there is a 10.57% probability that the mean contents of the 625 sample cans is less than 9.995 ounces.

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2 years ago
The zeroes of f(x) = x3 + 3x2 + 2x
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Answer:

the answers are -2,-1,0

Step-by-step explanation:

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We want to draw a conclusion about the scale factor for the dilation shown by only watching the given graph, the only conclusion we can take is that a scale factor is a number between 0 and 1. So we have a transformation that transforms the triangle ABC into the triangle A'B'C'.You can see that it is a dilation about the black dot seen in the given image, if the scale factor was a number larger than 1, then the dilated points would be further away from the black dot. But that is not the case, we can see that the images of the dilation are closer to the black dot, then this is not a "real" dilation, this is actually a contraction (where a contraction is a "dilation" of scale factor between zero and 1). Then the only thing that we can conclude with the given image is that the scale factor of the dilation shown is a number larger than 0 and smaller than 1.

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