triangle RST is congruent to triangle NPQ, RT=7x-5, NQ= 5x+11, find the length of side RT and side NQ
2 answers:
Answer: The length of side RT and side NQ is 51 units.
Step-by-step explanation:
Given : Δ RST ≅ Δ NPT
RT=7x-5 , NQ= 5x+11
To find: RT =? and NQ=?
Solution:
Since, given triangles are congruent .And Congruent triangles have equal sides.
≅
So,
RT= NQ = 7x-5 = 5x+11
Solving for x we get ,x = 8
RT =7x-5 = 7 × (8) - 5 = 51 units
NQ = 5x+11 = 5 × (8) + 11 = 51 units
7x + 5 = 5x + 11
2x + 5 = 11
2x = 6
x = 3
7(3) + 5
21 + 5 = 26
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