5 times 40 times 49 equals 9800 because you do 5 time 4 and that's 20 and you add a 0 and you multiply by 49 to get 9800.
Answer:
5.33333333...
Step-by-step explanation:
it will be like -5 out the bracket x - 3 x which gives you 15 then we'll check again - 5 then you times it by there 10 in the bracket and then it gives you 50 and then it will be there in 15 x - 50 equals to 30 then you take the -50 to the other side where there is 30
then it will be 15 x equals to 30 + 50 and then then 15 x equals to 8 and then you divide both of the sides with 15 then get your answer
-5 (-3x+10)=30
15x-50=30
15x=30+50
15x/15=80/15
x=5.33333...
Lol I'll just comment to get 5 points
Let the one type of the bread be bread A
The second type of the bread be bread B
Let the flour be 'f' and the butter be 'b'
We need 150f + 50b for bread A and 75f + 75b for bread B
We can compare the amount of flour and bread needed for each bread and write them as ratio
FLOUR
Bread A : Bread B
150 : 75
2 : 1
We have a total of 2250gr of flour, and this amount is to be divided into the ratio of 2 parts : 1 part. There is a total of 3 parts.
2250 ÷ 3 = 750 gr for one part then multiply back into the ratio to get
Bread A : Bread B = (2×750) : (1×750) = 1500 : 750
BUTTER
Bread A : Bread B = 50 : 75 = 2 : 3
The amount of butter available, 1250 gr is to be divided into 2 parts : 3 parts.
There are 5 parts in total
1250 ÷ 5 = 250 gr for one part, then multiply this back into the ratio
Bread A: Bread B = (2×250) : (3×250) = 500 : 750
Hence, for bread A we need 1500 gr of flour and 500 gr of butter, and for bread B, we need 750 gr of flour and 750 gr of butter.
six
Step-by-step explanation:
the reason is this: let steak be (s), pork be (p), grilled chicken be (gc), tea be (t), and coffee be (c)
now, we want to find the total number of outcomes, and this cannot be determined by a simple roll of the dice. you have to count the sample space required for EVERY outcome, and it has to lie within the conditions. so, assuming David only takes 1 main course and 1 drink, he would be down to six option, which are :
1. s & t
2. s & c
3. p & t
4. p & c
5. gc & t
6. gc & c