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pogonyaev
3 years ago
13

Solve: 3x-5y= -15 using y=mx+b method. Show steps

Mathematics
2 answers:
Anna007 [38]3 years ago
5 0
3x-5y=-15

-5y=-3x-15

-5y=-3x - 15

Y=3/5x+3

Sliva [168]3 years ago
4 0
3x-5y=-15                                What you do to one side, you must do to the other.
-<u>3x        -3x
</u><u />-5y=-3x-15

<u>-5y</u>=<u>-3x</u> <u>- 15</u>
-5     -5   -5

Final Answer: y=3/5x + 3

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What integer values for a and b would make the following statement true?
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2 years ago
An M&amp;Ms factory produces 109,500,000 M&amp;M’s every day. About 1/5 of its M&amp;Ms are yellow. Find the number of yellow M&
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The first thing to note is that the amount of yellow M&Ms isn't precisely 1/5th. It's about 1/5th.

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2 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
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Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

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2 years ago
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