Answer:
We can not solve for a unique cost for each soldier.
Step-by-step explanation:
Let x be the daily cost for legionaries and y be the daily cost for archers.
Upon using our given information we will get a system of linear equations as:


Now we will solve for x from our 2nd equation,

Now we will substitute this value in our 1st equation.

We can see that -3y cancels out with 3y and 9 is not equal to 10. So this is an unsolvable system. Therefore, we can not find a unique cost for each soldier.
Answer:
See below
Step-by-step explanation:
Only 'improper' fractions would have this result....that is fractions with numerator > denominator
80
Step-by-step explanation:
5×6 = 30 and 30×8 = 240 divide that by three you get 80
Step-by-step explanation:
you cant add 1 to 5x, so subtract 1 on both sides leaving you with 1 + 5x < 4 that equals 5x < 3 -1 -1
then divide 5 from both sides 5x < 3 This leaves 5 5
you with x < 3/5
Answer:
10 is the answer
Step-by-step explanation: