Question

8(t+2)-3(t-4)=6(t-7)+8

Answer 1

PEMDAS
the first thing is multiply or distribute
a(b+c)=ab+ac
8(t+2)=8t+16
-3(t-4)=-3t+12
6(t-7)=6t-42
the equation comes out to
8t+16-3t+12=6t-42+8
add like terms
5t+28=6t-34
subtract 5t from both sides
28=t-34
add 34 to both sides
62=t