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vaieri [72.5K]
3 years ago
8

A cone has a diameter of 18 units and height of 8 units. What is its volume? 72π cubic units 216π cubic units 648π cubic units 8

64π cubic units
Mathematics
2 answers:
Pavlova-9 [17]3 years ago
6 0

Answer:

Option (a) is correct.

The volume of given cone is 72π cubic units.

Step-by-step explanation:

Given : A cone has a diameter of 18 units and height of 8 units.

We have to determine the volume of the given cone.

We know Volume of cone = \frac{1}{3} \pi r^2 h

Where r is radius of cone

h is the height  of cone

Given : diameter = 18units  so, radius is half of diameter = 9 units

height = 8 units

Substitute, we have,

Volume of cone = \frac{1}{3} \pi\cdot (9)^2\cdot 8

Simplify, we have,

Volume of cone = 72\pi

Thus, the volume of given cone is 72π cubic units.

Option (a) is correct.

ANTONII [103]3 years ago
5 0
B 216 because if you multiply pi with the answer you get 678.58
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This question is incomplete, the complete question is;

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Answer:

a) E[G] is [ 0, 1 , 2 ]

b)

the distribution over the random variable G.

x     P(x)

0     0.0667

1      0.4667

2     0.4667

Step-by-step explanation:

Given the data in the question;

Number to be chosen is 2

from 7 girls and 3 boys

a) range of G

number of girls can be; [ 0, 1 , 2 ]

Therefore, E[G] is [ 0, 1 , 2 ]

b) he distribution over the random variable G.

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so

with P( G=g ) = P( getting g girls from 7 and 2-g boys from 3)

= ((^7C_g) × (^3C_{2-g)) / ^{10}C_2

now since, the range of G is [ 0, 1 , 2 ]

P( G=0 ) = ((^7C_0) × (^3C_{2)) / ^{10}C_2

= [(7!/(0!(7-0)!)) × (3!/(2!(3-2)!))] / (10!/(2!(10-2)!))

= [1 × 3] / 45 = 3/45 = 0.0667

P( G=1 ) = ((^7C_1) × (^3C_{1)) / ^{10}C_2

= [(7!/(1!(7-1)!)) × (3!/(1!(3-1)!))] / (10!/(2!(10-2)!))

= [ 7 × 3 ] / 45 = 21/45 = 0.4667

P( G=2 ) = ((^7C_2) × (^3C_{0)) / ^{10}C_2

= [(7!/(2!(7-2)!)) × (3!/(0!(3-0)!))] / (10!/(2!(10-2)!))

= [ 21 × 1 ] / 45 = 21/45 = 0.4667

Therefore, the distribution over the random variable G.

x     P(x)

0     0.0667

1      0.4667

2     0.4667

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