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Luden [163]
3 years ago
15

You are making fruit baskets using 54 apples, 36 oranges, and 73 bananas. a. Explain why you cannot make identical fruit baskets

without leftover fruit.b. What is the greatest number of identical fruit baskets you can make with the least amount of fruit left over? Explain how you found your answer
Mathematics
1 answer:
Basile [38]3 years ago
3 0
Question 1:
73 is a prime number. It can only be divided by 1 and by itself. 

The GCF of the three numbers:
 54                               36                            73
1×54                           1×36                          1×73
2×27                          2×18
3×18                           3×12
6×9                            4×9
                                   6×6

GCF of 54, 36 and 73  is 1

GCF of 54 and 36 is 18

If we divide 54 apples into 18 baskets, we have 3 apples in each basket
If we divide 36 oranges into 18 baskets, we have 2 oranges in each basket
If we divide 73 bananas into 18 baskets, we have 4 bananas in each basket + one banana left over.

So the greatest number of identical fruit baskets we can make with the least amount of fruit left over is 18 baskets
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4 years ago
Explain how to use a pattern to find 35.6 divided by 10 to the power of 2
posledela
As we know, sometimes questions such as these that include the powers and patterns can be a little confusing. I'll walk you through the process of finding this answer.

Firstly, we both know that 10 to the power of 2 simply means this :

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4 0
3 years ago
Help me please<br>help.me​
levacccp [35]

Answer:

The answers of the questions are given below :

  • a) = 4096
  • b) = 1.25
  • 3) = m²
  • 4) = r⁴s³
  • 5) = a⁸/b¹²

Step-by-step explanation:

\large{\tt{\underline{\underline{\red{QUESTION}}}}}

\begin{gathered}\footnotesize\boxed{\begin{array}{c|c|c}\bf\underline{Given}&\bf\underline{Solution}&\bf{\underline{Simple\: Form}}\\\\\rule{60pt}{0.5pt} &\rule{70pt}{0.5pt}& \rule{70pt}{0.5pt}\\\\ 1.\: {4}^{6} & & \\\\ 2.\: \bigg(\dfrac{2^6}{5^3} \bigg)& &\\\\  3. \: \Big({m}^{\frac{2}{3}}\Big)\bull \Big({m}^{\frac{4}{3}}\Big) & &\\\\4. \:  \big({r}^{12} {s}^{9}\big)^{ - \frac{1}{3}} &&\\\\ 5.\bigg(\dfrac{a^4}{a^6}\bigg)^{2}& &\end{array}}\end{gathered}

\begin{gathered}\end{gathered}

\large{\tt{\underline{\underline{\red{SOLUTION}}}}}

Question. 1

>> 4⁶

\begin{gathered}\qquad{= 4 \times 4 \times 4 \times 4 \times 4 \times 4} \\  \qquad{= 16 \times 4 \times 4 \times 4 \times 4} \\ \qquad{= 64 \times 4 \times 4 \times 4} \\ \qquad{= 256\times 4 \times 4} \\ \qquad{= 1024  \times 4} \\ \qquad{= 4096} \end{gathered}

  • Hence, the answer is 4096.

\begin{gathered}\end{gathered}

Question. 2

>> (2⁶/5³)^-⅓

\begin{gathered} \qquad\implies{\bigg(\frac{2^6}{5^3}\bigg)^{ - \frac{1}{3}}}\\  \\ \qquad\implies{\bigg(\frac{64}{125}\bigg)^{ - \frac{1}{3}}}\\  \\\qquad\implies{\bigg( \frac{1}{\frac{64}{125}}\bigg)^{ \frac{1}{3}}} \\  \\ \qquad\implies{\bigg( 1 \times  \frac{125}{64} \bigg)^{ \frac{1}{3}}} \\  \\ \qquad\implies{\bigg( \frac{125}{64} \bigg)^{ \frac{1}{3}}} \\  \\\qquad\implies{\bigg( \sqrt[3]{ \frac{125}{64}}\bigg)}  \\  \\ \qquad\implies{\bigg( \dfrac{5}{4} \bigg)} \\  \\ \qquad\implies{\Big( 1.25\Big)}\end{gathered}

  • Hence, the answer is 1.25.

\begin{gathered}\end{gathered}

Question. 3

>> (m^2/3)•(m^4/3)

\begin{gathered} \qquad{=  \Big({m}^{\frac{2}{3}}\Big) \bull \Big({m}^{ \frac{4}{3}}\Big)} \\  \\ \qquad{=  \Big({m}^{\frac{2}{3} +  \frac{4}{3}}\Big)} \\  \\ \qquad{=  \Big({m}^{\frac{2 + 4}{3}}\Big)} \\  \\ \qquad{=  \Big({m}^{\frac{6}{3}}\Big)} \\  \\ \qquad{=  \Big({m}^{2}\Big)}\end{gathered}

  • Hence, the answer is m².

\begin{gathered}\end{gathered}

Question. 4

>> (r¹² s⁹)^⅓

\begin{gathered} \qquad\implies{\Big( {r}^{12} \: {s}^{9}\Big)^{\frac{1}{3}}}\\\\ \qquad\implies{\Big({r}^{\frac{12}{3} } \: {s}^{\frac{9}{3}}\Big)}  \\  \\ \qquad\implies{\Big({r}^{\cancel{\frac{12}{3}}} \: {s}^{\cancel{\frac{9}{3}}}\Big)}  \\  \\ \qquad\implies{\Big({r}^{4} \: {s}^{3}\Big)} \end{gathered}

  • Hence, the answer is r⁴s³.

\begin{gathered}\end{gathered}

Question. 5

>> (a⁴/b⁶)^2

\begin{gathered} \qquad{ =  \Big(\frac{a^4}{b^6}\Big)^{2}} \\ \\  \qquad{ =  \Big(\frac{a^{4 \times 2}}{b^{6 \times 2}}\Big)} \\ \\ \qquad{ =  \Big(\frac{a^{8}}{b^{12}}\Big)} \end{gathered}

  • Hence, the answer is a⁸/b¹².

\underline{\rule{220pt}{3pt}}

4 0
2 years ago
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