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Aleksandr [31]
4 years ago
15

HELP— graphing get marked brainliest

Mathematics
1 answer:
34kurt4 years ago
4 0

Answer: Point C

You can see on the graph that it’s -3 (3 to the left of 0) and it’s -2 (2 below the x axis)

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How could you use the distributive property to rewrite -18+(-27)
anastassius [24]

Answer:

Here are just three examples I came up with:

-9(2 + 3)

or

-3(6 + 9)

or

-(18 + 27)

Step-by-step explanation:

  • To come up with these expressions, I found common factors between the numbers -18 and -27.
  • Then, I factored the numbers with the common factor (the common number is the number outside of the parentheses.)
  • When you distribute any of the expressions above, you will find they they can be simplified to -18 - 27, which is the same as -18 + (-27).
3 0
3 years ago
Read 2 more answers
Hello!) Can you help me please?
OLga [1]

3)

f(n) = 4 x 1 + 5 = 9

f(n) = 4 x 2 + 5 = 13

f(n) = 4 x 3 + 5 = 17

f(n) = 4 x 4 + 5 = 21

4)  

f(n) = 3(1-2) - 4 = -7

f(n) = 3(2-2) - 4 = -4

f(n) = 3(3-2) - 4 = -1

f(n) = 3(4-2) - 4 = 2


5)

f(n) = 3n - 4

n = 17


5 0
3 years ago
Find the length of the diagonal for a square that is 6 cm. by 6 cm. Leave answer in simple radical form, if necessary.
dexar [7]

Answer:

6\sqrt{2}

Step-by-step explanation:

let the diagonal be d

using the pythagoras theorem,

6^{2} + 6^{2} = d^{2}

d=\sqrt{72}

which in radical form is

6\sqrt{2}

4 0
3 years ago
If Michael's family has 210 acres and each cow take 1/3 acre for grazing, how many cattle could their farmland support?
Semenov [28]

630 acres

Since 1 cow takes \frac{1}{3} of an acre for grazing that means you can have 3 cattle per acre so simply do 210×3 to get 630

3 0
4 years ago
Read 2 more answers
Solve the system by substitution.<br> y = 4x – 8<br> Y = 2x
enyata [817]

first one if u solve for y is   y=4x-8

solve for x is x =y/4+2

second one is if u solve for y is y=2x

if u solve for x is x =y/2

Step-by-step explanation:

hope this help

4 0
3 years ago
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