Answer:
q=3.5*10^-4
Explanation:
<u>concept:</u>
The force acting on both charges is given by the coulomb law:
F=kq1q2/r^2
the centripetal force is given by:
Fc=mv^2/r
The kinetic energy is given by:
KE=1/2mv^2
<u>The tension force:</u>
<u><em>when the plane is uncharged </em></u>
T=mv^2/r
T=2(K.E)/r
T=2(50 J)/r
T=100/r
<u><em>when the plane is charged </em></u>
T+k*|q|^2/r^2=2(K.E)charged/r
100/r+k*|q|^2/r^2=2(53.5 J)/r
q=√(2r[53.5 J-50 J]/k) √= square root on whole
q=√2(2)(53.5 J-50 J)/8.99*10^9
q=3.5*10^-4
Answer:
<h2>48,000 J</h2>
Explanation:
The kinetic energy of an object can be found by using the formula
m is the mass
v is the velocity
From the question we have
We have the final answer as
<h3>48,000 J</h3>
Hope this helps you
Answer:
962.5 Hz
Explanation:
given,
frequency = 8.94 GHz
speed of the trap = 32.3 m/s
frequency shift = ?
frequency of shift is calculated using formula
c is the speed of light
f_o is the frequency of the radar gun
the frequency of shift is equal to 962.5 Hz
Answer:
Explanation:
mass of alpha particle, m = 4 u = 4 x 1.67 x 10^-27 kg
charge, q = 2 e = 3.2 x 10^-19 C
radius, r = 3.45 cm
Magnetic field, B = 1.67 T
(a) let v be the speed
v = 2760000 m/s
(b) Let T be the period of revolution
T = 7.85 x 10^-8 seconds
(c) Kinetic energy, K =0.5 x mv²
K = 0.5 x 4 x 1.67 x 10^-27 x 2760000 x 2760000
K = 6.36 x 10^-15 J
(d) kinetic energy, K = e V
where, V is the potential difference
6.36 x 10^-15 = 1.6 x 10^-19 x V
V = 39754.35 V
Answer:
Galaxies move in a random pattern.