Answer:
(a). The distance from the initial position is 6.68 km.
(b). The magnitude of their displacement is 7.05 km.
Explanation:
Given that,
Geese fly 4.0 km due west, then turn to north by 40° and fly another 3.5 km.
(a). We need to calculate the distance from the initial position
Using formula of distance
Put the value into the formula
(b). We need to calculate the magnitude of their displacement
Using formula of displacement
Hence, (a). The distance from the initial position is 6.68 km.
(b). The magnitude of their displacement is 7.05 km.
Answer: Average Velocity = - 643.42 i + 512.66 j m/s
Magnitude = 822.7 m/s
Direction = 141.45°
Explanation:
r = 3.84 x 10^8 m
w = 2.46 x 10^-6 rad/s
Formula for Average velocity = displacement / time
at t = 0
x(0) = r
y(0) = 0
at t = 8.45 days
= 8.45 x 24 x 3600 s =730080 sec
w t = 2.46 x 10^-6 x 730080 = 1.80 rad Or 102.90°
xf = r cos(w t) = - 0.2233r
yf = r sin(w t) = 0.9747r
Displacement = (xf - x0)i + (yf - y0)j = -1.2233r i + 0.9747r j
<v> = dispalcement / t = (-1.2233r i + 0.9747r j ) / (730080 s )
= - 643.42 i + 512.66 j m/s
Magnitude
= sqrt(643.42^2 + 512.66^2)
= 822.7 m/s
Direction
= 180 - tan^-1(512.66 / 643.42)
= 141.45°
C. position of the object
Hope it helps! :)
