Given the coordinates of the image of line segment RT to be R'(-2,-4) and T'(4.4), if the image produced was dilated by a scale factor of 12 centered at the origin, to get the coordinate of the end point, we will simply multiply the x and y coordinates of by the factor of 12 as shown:
For R' with coordinate R'(-2,-4), the coordinates of endpoint of the pre-image will be:
R = 12R'
R = 12(-2, -4)
R = (-24, -48)
For T' with coordinate T'(4,4), the coordinates of endpoint of the pre-imagee will be:
T = 12T'
T = 12(4, 4)
T = (48, 48)
Hence the coordinate of the endpoint of the preimage will be at R(-24, -48) and T(48, 48)
Answer:
In the last two overs, the bowler gave 14 runs.
Step-by-step explanation:
The bowling rate of 4.5 in the first 8 over means he gave 32.5 runs.
i.e.
Score given in first 8 overs = 4.5 × 8 = 36
Given that the bowling economy 5 at the end of 10 overs means the bowler must have given 10 × 5 = 50 score in the total 10 overs.
so, subtract 36 from 50 to get the score he will be giving in the last two overs.
i.e. score given the last two overs = 50 - 36 = 14
Therefore, in the last two overs, the bowler gave 14 runs.
Coefficient is 4
Constant is 5
There is 2 terms
Hope this helped!
