Considering the given figure, the conjecture with the rephrased statement of proof to show the diagonals of a parallelogram bisect each other is: In parallelogram EFGH show EK is congruent to KG and F.K is congruent to KH
<h3>How to determine the correct rephrase of the proof about parallelogram diagonals</h3>
The diagonals refer to the lines running between the two opposite ends of the parallelogram
Bisecting means sharing into two equal parts
congruent means a copy that is equal in dimension hence can be used in place of the other image
The diagonals of a parallelogram bisect each other means that the diagonals cut each other to form two equal parts such that each part is congruent to each other.
Learn more on diagonals of a parallelogram
brainly.com/question/17920093
#SPJ1
Do you have a picture of the graph, I cant help u with out it. :)
Since y=-1 when x=0 and we can write the equation (we'll turn it into an inequality later) as y=mx-1 from y=mx+b by plugging (0,1) in. Next, y equals 2 when x=1, so we plug those in to get 2=m*1-1. Adding 1 to both sides, we get 3=m, making our equation y=3x-1 (since y and x stay variables). Lastly, we turn it into an inequality, It seems to be inclusive to the line, so it's either
3x-1≤y or 3x-1≥y. Finding a random point in the inequality (4, 1), we plug it in to get 12-1=11, which is clearly larger than 1, so we get 3x-1≥y.
(x+3)(x+3) = x^2 -3 + 3x
x^2 + 3x + 3x + 9 = x^2 + 3x - 3
x^2 + 6x + 9 = x^2 + 3x - 3
6x + 9 = 3x - 3
3x + 9 = -3
3x = -12
x = -4
Check:
(-4+3)^2 = (-4)^2 - 3(1+4)
(-1)^2 = 16 - 3(5)
1 = 16-15
1 = 1 :)
