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Artyom0805 [142]
3 years ago
11

Given f(x) = 5x - 4, find f(2).

Mathematics
2 answers:
Vilka [71]3 years ago
6 0

Answer:

6

Step-by-step explanation:

f(x)=5x-4

f(2)=5(2)-4

10-4=6

babymother [125]3 years ago
6 0
Replace the x with 2
After u will be left with 10-4
Which = 6
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kramer
<h3>Function 1 : </h3>

Observe the abscicca and ordinates

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>y-coordinate</em><em> </em><em>is</em><em> </em><em>ordinate</em><em> </em><em>and</em><em> </em><em>x-coordinate</em><em> </em><em>is</em><em> </em><em>abscicca</em><em>.</em>

  • The ordinate having 0 as abscicca in function 1 is (0,1), Thus.. The y-intercept is 1

<h3>Function 2 : </h3>

Observe the graph and mark the point where function meets y-axis

<u>*</u><u>Note</u><u> </u><u>that</u><u>:</u><u>-</u><u> </u><em>The</em><em> </em><em>point</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>graph</em><em> </em><em>where</em><em> </em><em>the</em><em> </em><em>function</em><em> </em><em>meets</em><em> </em><em>y-axis</em><em> </em><em>is</em><em> </em><em>called</em><em> </em><em>y-intercept</em><em>.</em>

  • The point where the function meets is (0,1). Therefore, The y-intercept of function 2 is also 1

\red{ \rule{35pt}{2pt}} \orange{ \rule{35pt}{2pt}} \color{yellow}{ \rule{35pt} {2pt}} \green{ \rule{35pt} {2pt}} \blue{ \rule{35pt} {2pt}} \purple{ \rule{35pt} {2pt}}

<em><u>Thus, Option C is the correct choice!!~</u></em>

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