The interquartile range = Third quartile - First quartile = 22 - 15 = 7
The range = 25 - 12 = 13
<h3>What is the
Interquartile Range (IQR) and Range ofa Data?</h3>
Range = largest data value - the least data value
Interquartile range = Q3 - Q1
Given the following weekly allowance of Sean's classmates as, 15, 15, 22, 14, 12, 24, 16, 25, 15, 15:
Third quartile (Q3) = 22
First quartile (Q1) = 15
Interquartile range = 22 - 15 = 7
Range = 25 - 12 = 13
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Answer:
For first part, t= 0.18 sec or 3.4 sec.
For second part, t= 3.7 sec.
Step by step answer:
First part:
Set h(t) = 17and solve for tt.
-16t²+ 58t + 7= 17
-16t² + 58t - 10 = 0
Solve this quadratic equation for t. You should get 2 positive solutions. The lower value is the time to reach 17 on the way up, and the higher value is the time to reach 17 again, on the way down.
Second part:
Set h(t) = 0 and solve the resulting quadratic equation for t. You should get a negative solution (which you can discard), and a positive solution. The latter is your answer.
2>8-4h/3 subtract 8 from both sides
-6>-4h/3 multiply both sides by 3
-18>-4h divide both sides by -4 (and reverse sign because of division by a negative value)
4.5<h or by convention...
h>4.5