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SSSSS [86.1K]
3 years ago
5

A company bought a total of 4 1/2 feet of cable to connect 3 computers to the wall outlet. Each computer needs the same amount o

f cable. How many feet of cable are needed to connect each computer?A.1 1/2 ft B.1/3 ft C.1 1/3 ft D.1/2 ft please help i will mark brainliest
Mathematics
1 answer:
Vladimir79 [104]3 years ago
4 0
A1 1/2 because 4 1/2 ÷3 = 1 1/2
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Greatest common factor M^3n and 5m^5n^2
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m³n

Step-by-step explanation:

8 0
3 years ago
Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?
Yanka [14]

Answer:

Step-by-step explanation:

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\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\

(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+  \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.

8 0
1 year ago
Add: 7/8 + 5/6 .......
Rashid [163]

Answer:

1 17/24

Step-by-step explanation:

To add fractions, find the LCD and then combine.

Exact Form:

41/24

Decimal Form:

1.7083

Mixed Number Form:

1 17/24

6 0
3 years ago
Read 2 more answers
Mr. Rudd built a cabin with 351 logs, and his friend built a cabin with 113 logs. About how many logs did the two of them use
seropon [69]

Answer:

464

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351 + 113. Add them both together to get your answer.

4 0
3 years ago
5 - 6 - 9 - 8 - 5 - 4 + 5 - 5 -5 -5 - 32 = ?
musickatia [10]

5 - 6 = -1

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-27 + 5  = -22

-22 - 5 = -27

-27 -5 = -32

-32 -5  = -37

-37 - 32 = -69

Answer = -69

6 0
3 years ago
Read 2 more answers
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