Answer:
The code to this question can be given as:
Code:
public interface Test
{
public abstract Duration getDuration();
public abstract Result check(int ar);
public abstract double getScore();
}
Explanation:
An interface is similar to Java Class, and it has only static variables and abstract methods. Java uses a multi-inheritance interface. Many Java interfaces can be implemented by a Java class. All methodologies were implicitly public and abstract within an interface.
In the given question we a function that is "Test" and inside the interface, we define three functions that are defined as:
- First, we declare a "getDuration" method that returns the Duration object.
- Second, we declare a "check" method that accepts an integer variable that is "a".
- Third, we declare a "getScore" method that returns a double value.
B. Iron is the correct answer
Answer:
Option A(True) is the correct answer for the above question.
Explanation:
- An array is used for the collection variables which is of the same type and uses memory in continuous Passion for the storage.
- When any user wants to use the array then he needs to declare the size and type of the array because array holds the same type of data.
- For example, int a[5] is an array of integer variable whose name is 'a' and the size is 5 in c language.
- Anyone can use the array with the help of the index value of the array. The starting index value is 0 and the ending index value is (size-1) for any array.
- The user can use it by the help of loop, in which the loop variable refers to the index of the array and it starts from 0 and ends in the (size of the array-1).
- It is because the loop executes the same line multiple times.
- The above statement also wants to state, which is defined as above. Hence the above statement is true which is referred by option A. Hence option A is the correct answer.
Answer:
communication devices
Explanation:
it is defined so in computer study
The principal investment required to get a total amount of $10,000.00 from compound interest at a rate of 13% per year compounded 1 times per year over 1.5 years is $8,324.96.
Answer:
P = $8,324.96
<h3>Compound Interest</h3>
Given Data
Final Amount A = $10,000
Time t = 1 year 6 months
Rate = 13%
Calculation Steps:
First, convert R as a percent to r as a decimal
r = R/100
r = 13/100
r = 0.13 per year,
Then, solve the equation for P
P = A / (1 + r/n)^nt
P = 10,000.00 / (1 + 0.13/1)^(1)(1.5)
P = 10,000.00 / (1 + 0.13)^(1.5)
P = $8,324.96
Learn more about compound interest here:
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