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Gekata [30.6K]
4 years ago
13

Find two consecutive integers such that the larger is nine more than twice the smaller

Mathematics
1 answer:
ivann1987 [24]4 years ago
6 0
A=b+1
a=2b+9

b+1=2b+9
-b from both sides
1=b+9
-9 from both sides
-8=b

b+1
-8+1
-7

You can check your answer...
2b+9
2(-8)+9
-16+9
-7

The smaller is -8 and the larger is -7
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