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Y_Kistochka [10]
3 years ago
12

Help with 8? I really need some help guys!

Physics
1 answer:
hjlf3 years ago
8 0

It sounds like you're supposed to find the average velocity \bar v over the total 3.8 seconds, which would be given by

\bar v=\dfrac{\Delta x}{\Delta t}=\dfrac{x-x_0}{t-t_0}

where x is the displacement at time t, x_0=0 is the initial displacement from the origin, and t_0=0 is the starting time. Then the average velocity over the total 3.8 seconds,

\bar v=\dfrac xt,

is determined entirely by the displacement of the particle after 3.8 seconds, so that

\bar v=\dfrac{-9.23\,\mathrm m}{3.8\,\mathrm s}\approx-2.4\,\dfrac{\mathrm m}{\mathrm s}

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a shot putter releases the shot some distance above the level ground with a velocity of 12.0 m/s, 51.0 ∘above the horizontal. th
Savatey [412]

Answer:

15.7 m

Explanation:

The range (horizontal distance) of the projectile is determined only by its horizontal motion.

The horizontal motion is a motion with constant speed, which is equal to the initial horizontal velocity of the object:

v_x = v cos \theta

where

v = 12.0 m/s is the initial velocity

\theta=51.0^{\circ} is the angle between the direction of v and the horizontal

Substituting,

v_x = (12.0 m/s)(cos 51.0^{\circ} )=7.55 m/s

We know that the projectile hits the ground in a time of

t = 2.08 s

so the horizontal distance covered is

d = v_x t = (7.55 m/s)(2.08 s)=15.7 m

8 0
2 years ago
A ball is thrown vertically downward at 10 m/s. what is it’s speed 1s and 2s later
soldi70 [24.7K]

Answer:

20 m/s

30 m/s

Explanation:

Given:

v₀ = -10 m/s

a = -9.8 m/s²

When t = 1 s:

v = v₀ + at

v = (-10 m/s) + (-9.8 m/s²) (1 s)

v = -19.8 m/s

When t = 2 s:

v = v₀ + at

v = (-10 m/s) + (-9.8 m/s²) (2 s)

v = -29.6 m/s

Rounded to one significant figures, the speed of the ball at 1 s and 2 s is 20 m/s and 30 m/s, respectively.

3 0
3 years ago
Which of the following is not considered a major work flow structure?
mixas84 [53]

Answer:

The correct option is;

D. Fabrication

Explanation:

A workflow flow is a detailed business process consisting of a series of required interconnected tasks in  directed graph format  that is executable by  workflow management system.

Considering each of the options, we have

A. Work center

This consists of part of the transformation input to output. The location

B. Project

This is the unique identifier of the task to be processed

C. Assembly line

Forms part of the required input where transformation takes place and items are being processed within the assembly line

D. Fabrication

Here the item is fixed, without motion, therefore this is not considered a major work flow structure

E. Continuous flow

Here again, the items are being processed and are in motion, which constitutes a workflow structure.

8 0
2 years ago
Let n represent the number of similar resistors in a circuit. Each resistor has a resistance of r. When the resistors are connec
jekas [21]
Resistance=(r1+r2+r3...)n
                   =n×r
8 0
3 years ago
Which instrument measure the intensity of sound​
professor190 [17]

Answer:

Decibel Meter

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3 0
2 years ago
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