Answer:
The substrate concentration reached Vmax
Explanation:
In this scenerio, further increase in the rate of reaction was prevented because the substrate concentration hit Vmax.
Beyond the Vmax, the substrate can no longer proceed.
- The substrate is the reactant on which the enzyme works on.
- Enzymes are natural organic chemical catalysts.
- Increasing the concentration of reactants is one of the known and proven ways to speed up the rate of reaction.
- Since we have limited amount of enzymes, once they all bound to the substrate, no further increase in the substrate will have an effect on the rate.
- At the optimum reaction point, all the available substrate will bond with the enzyme.
- Beyond this, the enzymes are saturated will not further any reaction.
The answer is Uranus, as it has a tilted axis.
Hi pupil here's your answer ::
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Newton's Second Law of motion states that the rate of change of momentum of an object is proportional to the applied unbalanced force in the direction of the force.
ie., F=ma
Where F is the force applied, m is the mass of the body, and a, the acceleration produced.
Or in simplest language it is the force applied to a particular object of particular mass multiplied by the acceleration caused by force .
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hope that it helps. . . . . .
Answer:
A) 12.57 m
B) 5 RPM
C) 3.142 m/s
Explanation:
A) Distance covered in 1 Revolution:
The formula that gives the relationship between the arc length or distance covered during circular motion to the angle subtended or the revolutions, is given as follows:
s = rθ
where,
s = distance covered = ?
r = radius of circle = 2 m
θ = Angle = 2π radians (For 1 complete Revolution)
Therefore,
s = (2 m)(2π radians)
<u>s = 12.57 m</u>
B) Angular Speed:
The formula for angular speed is given as:
ω = θ/t
where,
ω = angular speed = ?
θ = angular distance covered = 15 revolutions
t = time taken = 3 min
Therefore,
ω = 15 rev/3 min
<u>ω = 5 RPM</u>
C) Linear Speed:
The formula that gives the the linear speed of an object moving in a circular path is given as:
v = rω
where,
v = linear speed = ?
r = radius = 2 m
ω = Angular Speed in rad/s = (15 rev/min)(2π rad/1 rev)(1 min/60 s) = 1.571 rad/s
Therefore,
v = (2 m)(1.571 rad/s)
<u>v = 3.142 m/s</u>
Momentum = (mass) x (speed)
Momentum = (70 kg) x (10 m/s)
<em>Momentum = 700 kg-m/s</em>
