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leva [86]
4 years ago
11

How do you round 363 to the nearest 10 and 100

Mathematics
1 answer:
sertanlavr [38]4 years ago
8 0
Round 6 up, because 5 or more go on, 4 and below ignore, same for three, You'd end up with 460
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I really need help on gradpoint I will mark you braniliest
insens350 [35]
Answer: I’ll say B. Infinity many solutions


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4 0
3 years ago
The mass of 100 tins of corned beef is 34 g. What is the mass, in grams (g), of 1 tin of corned beef?
puteri [66]

Answer:

solution

100 tins of corned beef =36 g

1 tin of corned beef = 36÷100=0.36

so, 1 tin of corned beef is 0.36 g.

8 0
3 years ago
Need help figuring out A=
Bogdan [553]
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5 0
3 years ago
Any1 can help me wif this explain every step of this
Marianna [84]

4a-[7-2(a+6)+5a]

4a-[7-2a-12+5a] :you distribute the 2 to the a and the 6

4a-[-5+3a] :you combine like terms(the 7&(-12) and the 2a&5a

4a+5-3a :you distribute the (-) to make +5 and -3a

a+5

7 0
4 years ago
The following question has two parts. First, answer part A. Then, answer part B.
Pie

Answer:

When you're talking factors, you're talking about some sort of integer; that's because “factors” depends on the concept of divisibility, which are virtually exclusive to integers. When you're talking “greater than”, you're excluding complex numbers (where the concept of ordering doesn't exist) and you're probably assuming positive integers. If you are, then no; no positive integer has factors that are larger than it.

If you go beyond positive numbers, that changes. 0 is an integer, and has every integer, except itself, as factors; since its positive factors are greater than zero, there are factors of zero that are greater than zero. If you extend to include negative numbers, you always have both positive and negative factors; and since all positive integers are greater than all negative integers, all negative integers have factors that are greater than them.

Beyond zero, though, no integer has factors whose magnitudes are greater than its own. And that's a principle that can be extended even to the complex integers

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
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