Ask question

Ask question

All categories

Ostrovityanka [42]

3 years ago

10

Of the 15-year-olds at a karate school, 5 have black belts and 9 have brown belts. Among the 16-year-olds, 13 have black belts a

nd 19 have brown belts. Which age group has a lower ratio of black belts to brown belts?

1 answer:

Effectus [21]3 years ago

5 0

Answer:

the 15 year olds do

Step-by-step explanation:

You might be interested in

A recent Harris poll asked a random sample of 1016 adults nation-wide whether or not they smoked cigarettes. 22% said they smoke

photoshop1234 [79]

Answer:

A recent Harris poll asked a random sample of 1016 adults nation-wide whether or not they smoked cigarettes. 22% said they smoked. Based on this sample, can you conclude that...

a.) The expected value for the percent of all adults world-wide who would say they smoked cigarettes is 22%?

b). The expected value for the percent of students at UI who would say they smoked cigarettes is 22%?

c). The expected value for the percent of professors at UI who would say they smoked cigarettes is 22%?

d). The expected value for the percent of all US adults who would say they smoked cigarettes is 22%?

The correct answer is

d).The expected value for the percent of all US adults who would say they smoked cigarettes is 22%?

Step-by-step explanation:

The expected value is arrived at by finding the product of a possible output and the probability that the output will occur and summing up the results. Expected value can be used for investment management to calculate options and make decisions most likely to bring about the desired gain. The random variable provides categorisation of the outcomes of the game while the expected provides the probability of aan outcome

In the above, the source of the sample is nationwide whereby 22 % said they smoked therefore it cannot be applied to a different population that has a different expected value for the same survey.

8 0

2 years ago

Reasoning If 1/2 of 1 is 1/2 what is 1/2 of 2,3 and 4

hichkok12 [17]

Answer:

half of 2 is 1, half of 3 is 1.5,half of 4 is 2.

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

H(x) = x3 + 7<br> Determine whether the function is one-to-one.

zubka84 [21]

Answer:

we conclude that the function is one-to-one.

Step-by-step explanation:

A function will a one-to-one function if it

passes the vertical line test to make sure it is indeed a function, and

also a horizontal line test to make sure it is it one-to-one.

In other words,

The function will be one-to-one if it passes the vertical line test, and also if the horizontal line only cuts the graph of the function in one place.

The reason is that there must be only one x-value for each y-value.

Given the function

$h\left(x\right)\:=\:x^3\:+\:7$

Have a look at the attached graph.

The red portion represents the graph of the function $h\left(x\right)\:=\:x^3\:+\:7$ .

The green portion represents the graph of x=2 which is basically a vertical line test. Vertical line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is indeed a function.

The blue line represents the graph of y=9, which is basically a horizontal line test. Horizontal line indicates that it cuts the cuts the graph of the function in one place. So it is clear that $h\left(x\right)\:=\:x^3\:+\:7$ is a one-to-one function, as there is only one x-value for each y-value.

Therefore, we conclude that the function is one-to-one.

6 0

3 years ago

-8 + x - 4 + 9x<br> Need help

irina [24]

Answer:

Step-by-step explanation:

-8+x-4+9x = -8-4+x+9x

= -12+10x

PLEASE MARK BRAINLIEST.

5 0

2 years ago

The average summer temperature in Anchorage is 69°F. If the daily temperature is normally distributed with a standard deviation

mafiozo [28]

Answer:

81.85%

Step-by-step explanation:

Given :

The average summer temperature in Anchorage is 69°F.

The daily temperature is normally distributed with a standard deviation of 7°F .

To Find:What percentage of the time would the temperature be between 55°F and 76°F?

Solution:

Mean = $\mu = 69$

Standard deviation = $\sigma = 7$

Formula : $z=\frac{x-\mu}{\sigma}$

Now At x = 55

$z=\frac{55-69}{7}$

$z=-2$

At x = 76

$z=\frac{76-69}{7}$

$z=1$

Now to find P(55<z<76)

P(2<z<-1)=P(z<2)-P(z>-1)

Using z table :

P(2<z<-1)=P(z<2)-P(z>-1)=0.9772-0.1587=0.8185

Now percentage of the time would the temperature be between 55°F and 76°F = $0.8185 \times 100 = 81.85\%$

Hence If the daily temperature is normally distributed with a standard deviation of 7°F, 81.85% of the time would the temperature be between 55°F and 76°F.

7 0

2 years ago