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4 years ago

12

What is the value of the underlined digit in the following number?

2 answers:

Monica [59]4 years ago

8 0

Well there is no number underlined but looking at the answer choices I can see that the underlined digit is the 9. the 9 is in the hundredths place indicating that the value of the 9 is 9 hundredths.

vodka [1.7K]4 years ago

8 0

I think it the first one

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Hi please i nedd help with these questions .

Vlad1618 [11]

Answer:

Step-by-step explanation:

#1:

$\frac{18m^2u}{16n^3v^2} \div \frac{24m}{15nu^3}*\frac{8n^2v^3}{30m^3u}$

division sign means that we flip the fraction

$\frac{18m^2u}{16n^3v^2} * \frac{15nu^3}{24m}*\frac{8n^2v^3}{30m^3u}$

now we can multiply all the constants together and all variables

$m: (m^2)/(m*m^4) = (m^2)/(m^4) = 1/(m^2)\\u: (u * u^3)/(u) = (u^4)/(u) = u^3\\n: (n*n^2)/(n^3) = 1\\v: (v^3) / (v^2) = v\\(18*15*8)/(16*24*30) = \frac{3}{16}$

now we can combine all the parts

$\frac{3u^3v}{16m^2}$

#2:

$\frac{24a^2b^3c}{9bc^3}\div\frac{4a^5bc^3}{27a^3b^2c}$

$\frac{24a^2b^3c}{9bc^3}*\frac{27a^3b^2c}{4a^5bc^3}$

$a: (a^2 * a^3)/(a^5) = 1\\b: (b^3 *b^2)/(b*b) = b^3\\c: (c*c)/(c^3*c^3)= 1/(c^4)\\(24*27)/(9*4)= 18$

$\frac{18b^3}{c^4}$

3 0

3 years ago

Read 2 more answers

Catherine has the following grades on her math tests: 80, 84, 92,95. If she gets a 100 on her last math test, what will her aver

Anarel [89]

Answer: 90.2

Reasoning: You add all grades together. Next you dived by 5 because their are 5 grades. You then revive an average of 90.2

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3 years ago

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BRAINIEST TO WHOEVER RIGHT THERES A BOTTOM ROW ON THE LADT BOX THAT SAYS TOTAL

stira [4]

Right Row Top Box = 598
Right Row Middle Box = 750
Bottom Row Left Box = 780
Bottom Row Middle Box = 568
Right Bottom Box = 1348

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3 years ago

P(x)=-3+4x when x=-2,0, and 5

pishuonlain [190]

-3 + 4x
-3 + 4(-2)
-3 - 8
-11

-3 + 4(0)
-3 + 0
-3

-3 + 4(5)
-3 + 20
17

3 0

3 years ago

PLEASE HELP ME!!!

Brums [2.3K]

Answer:

$\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}$

Step-by-step explanation:

$5x^2-13x+7=0$

$x=\dfrac{13\pm \sqrt{169-140}}{10}=\frac{13+\sqrt{29}}{10} , \frac{13-\sqrt{29}}{10}$ . Hope this helps!

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3 years ago

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