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3 years ago

Work out the value of 5x-2y when x=-2 and y=-3

1 answer:

max2010maxim [7]3 years ago

3 0

I guess this how it would go
(5)(−2)−(2)(−3)

So your answer should be −4

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300 mi /20 sec = ? Mi /1 min

snow_lady [41]

Answer:

900

Step-by-step explanation:

To get your answer, you can just multiply 20 seconds by 3 to get 60 seconds, which is a minute.

Since whatever you do on one side you have to do to the other, multiply 300 mi by 3 as well. That would get you 900.

4 0

3 years ago

Determine the distance between the following two points. (round to the nearest hundredths)

padilas [110]

Answer:

$d=7.07$

Step-by-step explanation:

Distance Formula: $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Simply plug in the 2 coordinates into the distance formula to find distance d:

$d=\sqrt{(3-(-2))^2+(-4-1)^2}$

$d=\sqrt{(3+2)^2+(-5)^2}$

$d=\sqrt{(5)^2+25}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

$d=7.07$

5 0

3 years ago

What is the measure of DE?

tatuchka [14]

Answer:

Step-by-step explanation:

Alright, lets get started.

The two chords are intersection each other at point B.

$DBE=ABC$

Both are opposite angles that is 39 degrees.

Angle ABC forms the arc AC which is given 41 degree.

The arc DE will be same length as arc AC because angle ABC and angle DBE are same that is 39 degrees.

So, arc DE = 41

So, the answer is DE = 41 degrees .... Answer : option D

Hope it will help :)

5 0

3 years ago

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The adjustment of the thickness of the lens to make close vision possible is ca

Savatey [412]

Answer: Accommodation

Step-by-step explanation:

Accommodation is the adjustment of the optics of the eye to keep an object in focus on the retina as its distance from the eye varies.

4 0

3 years ago

Please help I suck at math and this is for a grade

qwelly [4]

C. negative exponents always go at the bottom

6 0

3 years ago

Read 2 more answers