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alekssr [168]
3 years ago
15

In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9

feet long?

Mathematics
2 answers:
Elis [28]3 years ago
5 0

Answer:

x=5\ ft

Step-by-step explanation:

we know that

The bar is 9 feet long

so

x+(x-1)=9

Solve for x

2x-1=9

2x=10

x=5\ ft

Verify

40x=50(x-1)

substitute the value of x

40(5)=50(5-1)

40(5)=50(4)

200=200 -----> the weights are perfectly balanced

creativ13 [48]3 years ago
4 0
So...we can write eqn as

40x = 50(x-1)
so. -10x=-50
so. x=5

therefore .... the distance of 40 lb will be 5 ft ...answer !!!
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MArishka [77]

Answer:

x = √39

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Trigonometry</u>

  • [Right Triangles Only] Pythagorean Theorem: a² + b² = c²

Step-by-step explanation:

<u>Step 1: Identify</u>

Leg <em>a</em> = <em>x</em>

Leg <em>b</em> = 5

Hypotenuse <em>c</em> = 8

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [PT]:                     x² + 5² = 8²
  2. Isolate <em>x</em> term:                       x² = 8² - 5²
  3. Exponents:                            x² = 64 - 25
  4. Subtract:                               x² = 39
  5. Isolate <em>x</em>:                               x = √39
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Answer:

3 HOURS : company A costs more

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10 HOURS : Company B costs more

Step-by-step explanation:

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Company B:

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Cost of renting a bounce house from each company for h hours ;

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Company B:

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Company B:

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Company B:

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FOR h = 10;

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Company B:

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3 years ago
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The answer is 7/10 because the even values are 2,4,6, and the others are 7,8,9,10. Added together, it adds up to 7/10
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Answer:

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