A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
__
a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
__
c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
The answer is A
Step-by-step explanation:
I solved using surface area
An=A1 r ^(n-1)
192= 3 r ^(4-1)
192 = 3 r^3
64 = r^3
r = 4
equation:
An=3 (4)^(n-1)
6th term:
An= 3 (4)^(6-1)
An= 3072
I think this is right :)
Answer:
Step-by-step explanation:
see the attached figure to better understand the problem
In the right triangle ABC
Applying the Pythagorean Theorem
substitute the given values
solve for BC
Answer:
Let total students who prefer lemonade is 2a and who prefer ice tea is a.
Students in 6th grade=39
2a+a=39
3a=39
a=39/3
a=13
students who prefer lemonate is 13
and those who prefer ice tea is 2a=26
