Question

In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9 feet long?

Answer 1

Answer:

$x=5\ ft$

Step-by-step explanation:

we know that

The bar is $9$ feet long

so

$x+(x-1)=9$

Solve for x

$2x-1=9$

$2x=10$

$x=5\ ft$

Verify

$40x=50(x-1)$

substitute the value of x

$40(5)=50(5-1)$

$40(5)=50(4)$

$200=200$ -----> the weights are perfectly balanced

Answer 2

So...we can write eqn as

40x = 50(x-1)
so. -10x=-50
so. x=5

therefore .... the distance of 40 lb will be 5 ft ...answer !!!