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alekssr [168]
3 years ago
15

In this fulcrum, the weights are perfectly balanced. How far must the fulcrum be located from the 40 lb. weight if the bar is 9

feet long?

Mathematics
2 answers:
Elis [28]3 years ago
5 0

Answer:

x=5\ ft

Step-by-step explanation:

we know that

The bar is 9 feet long

so

x+(x-1)=9

Solve for x

2x-1=9

2x=10

x=5\ ft

Verify

40x=50(x-1)

substitute the value of x

40(5)=50(5-1)

40(5)=50(4)

200=200 -----> the weights are perfectly balanced

creativ13 [48]3 years ago
4 0
So...we can write eqn as

40x = 50(x-1)
so. -10x=-50
so. x=5

therefore .... the distance of 40 lb will be 5 ft ...answer !!!
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