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2 years ago

Solve the following compound

Mathematics

1 answer:

hammer [34]2 years ago

5 0

Answer:

b<-12 or b>-12

(-∞,-12]U[-12,∞)

Step-by-step explanation:

0.5b > -6 or 3b + 16 <-8 + b

I solve these separately

0.5b > -6

Divide by .5 on each side

0.5b/.5 > -6/.5

b >-12

3b + 16 <-8 + b

subtract b from each side

3b-b + 16 <-8 + b -b

2b+16<-8

Subtract 16 from each side

2b+16-16<-8-16

2b< -24

Divide each side by 2

2b/2 <-24/2

b<-12

b<-12 or b>-12

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Answer:

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Step-by-step explanation:

$(x^{3} x^{-6} )^{2}$ is the expression given to be solved.

First of all let us have a look at 3 formulas:

$1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}$

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Applying formula (1):

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Answer:

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