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3 years ago

The equation with the restriction x, is on the terminal side of an angle in standard position.

1 answer:

5 0

4 because it hits the dextran quadran of the terminal side in a standered position while also...

just imagin a triange with four on top and -2 on side

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Find all numbers whose absolute value is – 3.

Gwar [14]

Answer:

remember that $|x|=x$ if $x\geq0$ and $|x|=-x \; \text{ if } x\leq 0$ . This means that $|x|$ always is a positive number.

Then, there are no numbers such that $|x|=-3$ because -3 is a negative number.

7 0

2 years ago

Your favorite restaurant has a promotion where you can win free food. You will roll 2 dice. The sum of the 2 dice will determine

nekit [7.7K]

Answer:

0.25

Step-by-step explanation:

edge '22

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1 year ago

What is the slope of a line that passes through (-12,15) and (0,4)

pav-90 [236]

Answer:

D. -11/12

Step-by-step explanation:

7 0

3 years ago

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

2 years ago

Simplify. √-64 A) -8 B) 8i C) -8i D) 32i

Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

√-64 = i√64 = 8i

6 0

2 years ago