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Drupady [299]
3 years ago
8

The equation with the restriction x, is on the terminal side of an angle in standard position.

Mathematics
1 answer:
marishachu [46]3 years ago
5 0
4 because it hits the dextran quadran of the terminal side in a standered position while  also...

just imagin a triange with four on top and -2 on side

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Find all numbers whose absolute value is – 3.
Gwar [14]

Answer:

remember that |x|=x if x\geq0 and |x|=-x \; \text{ if } x\leq 0. This means that |x| always is a positive number.

Then, there are no numbers such that |x|=-3 because -3 is a negative number.

7 0
2 years ago
Your favorite restaurant has a promotion where you can win free food. You will roll 2 dice. The sum of the 2 dice will determine
nekit [7.7K]

Answer:

0.25

Step-by-step explanation:

edge '22

6 0
1 year ago
What is the slope of a line that passes through (-12,15) and (0,4)​
pav-90 [236]

Answer:

D. -11/12

Step-by-step explanation:

7 0
3 years ago
How to prove this???
swat32
\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3)  \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 


go to right side now

4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)

use x^3 - y^3 = (x-y)(x^2 + xy + y^2) and x^3 + y^3 = x^2 - xy + y^2

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side
4 0
2 years ago
Simplify. √-64 A) -8 B) 8i C) -8i D) 32i
Vedmedyk [2.9K]

Answer:

C

Step-by-step explanation:

8i

√-64 = i√64 = 8i

6 0
2 years ago
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