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Ksju [112]
2 years ago
10

The length of the longer leg of a right triangle is

Mathematics
1 answer:
Harman [31]2 years ago
3 0
A and b are legs
a^2+b^2=c^2
lets say
a>b

so
a=13+3b
c=14+3b

a^2+b^2=c^2
(13+3b)^2+b^2=(14+3b)^2
9b^2+78b+169+b^2=9b^2+84b+196
10b^2+78b+169=9b^2+84b+196
minus 9b^2 both sides
b^2+78b+169=84b+196
minus 84b both sides
b^2-6b+169=196
minus 196 both sides
b^2-6b-27=0
factor
(b+3)(b-9)=0
set to zero
b+3=0
b=-3, false, dimentions cannot be negative

b-9=0
b=9

shorter leg is 9

a=13+3b
a=13+3(9)
a=13+27
a=40

c=14+3b
c=14+27
c=41

side legnths are
9in, 40in, 41in
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Hello there! The answer to your question is a = 4.

To solve for a in the equation -4 + 4a = 12 you want to isolate, or separate, a from all of the equation's other values.

Our first step is to add 4 to both sides so the 4 cancels out on the left side.

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Next, we divide both sides by 4 to finish isolating a.

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Want to verify that this is correct? Place the value we found for a (4) into the equation in place of a and if it comes out as a true statement, the answer is correct.

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Since 12 is in fact equal to 12, i can guarantee you that i have provided you with the correct answer. I hope this helps & have a great rest of your day! :)

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