Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Answer:
case A. 
case B. 
case E. 
Step-by-step explanation:
we have

we know that

<u>Verify each case</u>
case A) 

therefore
is equivalent to 
case B) 
so
is equivalent to 
case C) 

therefore
is not equivalent to 
case D) 
so
is not equivalent to 
case E) 

therefore
is equivalent to 
case F) 
so
is not equivalent to 
Answer:
36.3 gallons
Step-by-step explanation:
14.5/.4 = 36.3
13 !!
52/13 = 4
91/13 = 7
Good Day !!
Liaaam66