Answer:
14 students
Step-by-step explanation:
Im not 100% sure so im sorry if wrong
The values of the variables are k = -6 , w = ± 9 , f = -7
Step-by-step explanation:
To solve these problems we will compare the elements inside the [ ]
[-12 , -w²] = [2k , -81]
[2f , 3] = [-14 , 3]
That mean:
1. -12 = 2k
2. -w² = -81
3. 2f = -14
∵ 2k = -12
Divide both sides by 2 to find k
∴ k = -6
∵ -w² = -81
Divide both sides by -1
∴ w² = 81
Take √ for both sides
∴ w = ± 9
∵ 2f = -14
Divide bith sides by 2
∴ f = -7
The values of the variables are k = -6 , w = ± 9 , f = -7
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The answer is C. 120
The solution can be derived by the formula 6P3.
6P3 = 6 * 5 * 4 = 120
120 different combinations can be made with the condition.
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Answer:
Chicken is $8
Duck is $5
Step-by-step explanation:
Step 1: Let
represent the cost of chickens and let
represent the cost ducks. Since we have two unknowns, we need two equations to find them.
Step 2: The total cost of chickens Michael sold last month can be shown as
, and the total cost of ducks he sold last month can beshown as
Since these together add up to 550, we get these equations:

We are also given that this month, Michael sold 44 chickens, and 36start text, 36 ducks, $532. This equaion can be expressed as:

Now that we have a system of the two equations, we can now go ahead and solve the two equations.
Step 3: We can now solve the system of equations by using the elimination method. Manipulate the equations so one of the variables has the same coefficients but with opposite signs.

Now eliminate 

When we solve the resulting equation, we obtain that
. Then, we can substitute this into one of the original equations and solve for
to obtain
.
Step 4: Recall that
denotes the cost of a chicken and
denotes the cost of a duck. Therefore, a chicken costs $8, and a duck costs $5