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Evgesh-ka [11]
3 years ago
6

I will brainliest if correct! The graph of an exponential model in the form y=aXb^x passes through the points (3,5) and (4,10).

Which point is also on the graph?

Mathematics
1 answer:
Ber [7]3 years ago
3 0

Answer:

I hope that help

Step-by-step explanation:

Any point on a two-dimensional graph can be represented by two ... For example, the point (2, 3) is two units to the right of the y-axis and three units ... and (x2, y2), you can define the exponential function that passes through these points by substituting them in the equation y = abx and solving for a and b.

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Solve the quadratic equation by completing the square. 6x2 + 4x - 5 = 0
Nikitich [7]

Answer:

$x_{1}=-\frac{2+\sqrt{34}}{6}$

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Step-by-step explanation:

Quadratic Equation given:

6x^2 + 4x - 5 = 0

Start dividing both sides by 6.

$\frac{6}{6} x^2 +\frac{4}{6} x - \frac{5}{6}  = \frac{0}{6} $

$x^2 +\frac{2}{3} x - \frac{5}{6}  = 0 $

$x^2 +\frac{2}{3} x = \frac{5}{6} $

Once, $\left( \frac{2}{3} \cdot \frac{1}{2} \right)^2=\frac{1}{9} $

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$x+\frac{1}{3}  =\pm\sqrt{\frac{17}{18}} }   $

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$\sqrt{\frac{17(18)}{18(18)}}= \sqrt{\frac{306}{324}}=\frac{3\sqrt{34} }{18} =\frac{\sqrt{34} }{6} $

Then,

$x+\frac{1}{3}  =\pm\frac{\sqrt{34} }{6}  $

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$x_{1}=-\frac{2+\sqrt{34}}{6}$

$x_{2}=-\frac{2-\sqrt{34}}{6}$

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3 years ago
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Step-by-step explanation:

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I believe I would be the last one D

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