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Evgesh-ka [11]
3 years ago
6

I will brainliest if correct! The graph of an exponential model in the form y=aXb^x passes through the points (3,5) and (4,10).

Which point is also on the graph?

Mathematics
1 answer:
Ber [7]3 years ago
3 0

Answer:

I hope that help

Step-by-step explanation:

Any point on a two-dimensional graph can be represented by two ... For example, the point (2, 3) is two units to the right of the y-axis and three units ... and (x2, y2), you can define the exponential function that passes through these points by substituting them in the equation y = abx and solving for a and b.

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If a number’s composite form is 343, which of the following shows its exponential form as a product of prime numbers? A.7 · 49 B
Levart [38]

Answer:

a is the answer

Step-by-step explanation:

7×7×7=343

7×7=49

49×7=343

8 0
3 years ago
Let a be an irrational number. Is 1/a rational or irrational
Marianna [84]

<u>1 is a rational number</u> because 1 can go into 1 when dividing. <u>Irrational numbers are mostly decimals. </u>

7 0
3 years ago
Read 2 more answers
9. Calcule el valor de la fuerza que experimenta un ascensor cuando levanta 150 kg en los siguientes casos: a) Cuando asciende c
GenaCL600 [577]

Answer:

a) La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) Por la fuerza de tensión sobre el cable del ascensor.

Step-by-step explanation:

a) La fuerza neta experimentada por el ascensor (F), en newtons, es:

F = m\cdot a (1)

Donde:

m - Masa, en kilogramos.

a - Aceleración, en metros por segundo cuadrado.

Si sabemos que m = 150\,kg y a = 4\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = 600\,N

La fuerza neta que experimenta un ascensor cuando asciende con una aceleración de 4 metros por segundo al cuadrado es 600 newtons hacia arriba.

b) Si sabemos que m = 150\,kg y a = -6\,\frac{m}{s^{2}}, entonces la fuerza neta del ascensor es:

F = m\cdot a

F = -900\,N

La fuerza neta que experimenta un ascensor cuando desciende con una aceleración de 6 metros por segundo al cuadrado es 900 newtons hacia abajo.

c) De manera simplificada, el ascensor experimenta dos fuerzas que definen la fuerza y aceleración netas: (i) La fuerza de tensión sobre el cable que traslada el ascensor y el peso total del ascensor, opuesta a la anterior y en función de la aceleración gravitacional. Puesto que la masa no varía en ningún caso, se concluye que el peso es constante, entonces la diferencia de valores se debe a la fuerza por tensión del cable. En el descenso, es fuerza es menor que en el ascenso.

8 0
3 years ago
I don't like word problems, i need help with this guys
alina1380 [7]
Okay so first we want to find out how many cans one person uses a year. To find this we divide 16,801 by 53 and we get 317 cans a year. Using this we can find how many cans 1,694,000 people use a year by multiplying the people by 317. You get 536,998,000 cans a year, which is your answer.
7 0
3 years ago
A researcher wishes to be 95% confident that her estimate of the true proportion of individuals who travel overseas is within 3%
andre [41]

Answer:  a) 683   b) 1067

Step-by-step explanation:

The confidence interval for population proportion is given by :-

p\pm z_{\alpha/2}\sqrt{\dfrac{p(1-p)}{n}}

a) Given : Significance level :\alpha=1-0.95=0.05

Critical value : z_{\alpha/2}}=\pm1.96

Margin of error : E=0.03

Formula to calculate the sample size needed for interval estimate of population proportion :-

n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.2(0.8)(\dfrac{1.96}{0.03})^2=682.951111111\approx683

Hence, the required sample size would be 683 .

b) If no estimate of the sample proportion is available then the formula to calculate sample size will be :-

n=0.25(\dfrac{z_{\alpha/2}}{E})^2\\\\=0.25(\dfrac{1.96}{0.03})^2=1067.11111111\approx1067

Hence, the required sample size would be 1067 .

3 0
3 years ago
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