All categories

3 years ago

10^2 + 15 - 12 + 90 - 45 x 13 - 11 =

Mathematics

1 answer:

Vladimir [108]3 years ago

8 0

-403
-403
-403
-403
-403

You might be interested in

A square has a diagonal length of 5 cm what is the area of a square

Alborosie

Answer:

Area of square = 12.48 cm^2

Step-by-step explanation:

Since the square has all sides equal, and when diagonal is made, square form two right angled triangles. Using Pythagoras theorem we can find the length of side of the square.

$c^2 = a^2 + b^2$

where c = 5cm and a==b (square has all sides equal)

Putting value of b = a

$(5)^2 = a^2 + a^2\\25 = 2 a^2\\25/2 = a^2\\=> a^2 = 12.5\\ => \sqrt{a^2} = \sqrt{12.5}\\=> a = 3.53\, cm$

So, length of side of square = 3.53

Area of square = (3.53)^2

Area of square = 12.48 cm^2.

5 0

3 years ago

Read 2 more answers

Find the domain and range of the relation: (-8,8),(-8,7),(-8,6),(-8,5). Then determine whether the relation is a function.

Andrej [43]

The domain is {-8}
The range is {5,6,7,8}
The relation is not a function as the domain value -8 maps to multiple values. All domain values in a relation needs to map to exactly one range value for it be a function.

8 0

4 years ago

Solve for x, need help asap!

Alexxx [7]

Let's solve for x using trigonometric relation ( Cos )

we know,

$\cos(30 \degree) = \dfrac{base}{hypotenuse} = \dfrac{ \sqrt{3} }{2}$

now

$\dfrac{x}{8} = \dfrac{ \sqrt{3} }{2}$

$x = 8 \times \dfrac{ \sqrt{3} }{2}$

$x = 4 \sqrt{3}$

hence, the value of x is $4 \sqrt{3}$

4 0

3 years ago

5l = 1.5 × 25<br><br><br><br> What is 1.5 × 25?

Valentin [98]

Answer:

What is 1.5 × 25?

37.5

7 0

3 years ago

Read 2 more answers

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$