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3 years ago

What number has the factors of 1,2,3,4,6,7,12,14,21,28,42,49,84,98,147,196,294

Mathematics

1 answer:

madreJ [45]3 years ago

4 0

1?? 1 has every number so... everything is a factor of 1.

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Sam spent $32.50 to take his girlfriend to the movies. He spent 40% on snacks and the remainder was spent on the two tickets. Ho

Scorpion4ik [409]

$32.50 X .4 = $13, 32.5-13=19.5, 19.5 divided 2 =$9.75

6 0

4 years ago

Solve for x show all work -2× + 5=4× -7

Anestetic [448]

5=4x+2x-7
5+7=6x
12=6x
12/6=6x/6
2=x

6 0

4 years ago

Read 2 more answers

A grocery store sells apple and oranges by the pound the cost of the apples is $1.30 the cost of the oranges is $1.84 how much m

Feliz [49]

Answer:

1.5 pounds of oranges cost $0.81 more than 1.5 pounds of apples

Step-by-step explanation:

1.5 pounds of apples = 1.5 × $1.30 = $1.95

1.5 pounds oforanges = 1.5 × $1.84 = $2.76

$2.76 - $1.95 = $0.81

7 0

3 years ago

Plz with steps .. it's very hard can anyone plz

liubo4ka [24]

Answer:

Step-by-step explanation:

$\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\frac{0}{0} \\\\we\ can \ use\ Hospital's\ Rule\\\\\\f(x)=\sqrt{2x}-\sqrt{3x-a} \qquad f'(x)=\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} \\\\g(x)=\sqrt{x} -\sqrt{a} \qquad g'(x)=\dfrac{1}{2\sqrt{x}} \\\\\\\displaystyle\ \lim_{n \to a} \dfrac{\sqrt{2x}-\sqrt{3x-a} }{\sqrt{x}-\sqrt{a}} =\lim_{n \to a} \dfrac{\dfrac{2}{2*\sqrt{2x}} -\dfrac{3}{2*\sqrt{3x-a}} }{\dfrac{1}{2\sqrt{x}} }\\\\$

$\displaystyle \lim_{n \to a} \dfrac{2\sqrt{x} }{\sqrt{2x}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}} =\lim_{n \to a} \dfrac{2 }{\sqrt{2}} -\dfrac{3*\sqrt{x} }{\sqrt{3x-a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3*\sqrt{a} }{\sqrt{2a}}\\\\\\=\dfrac{2}{\sqrt{2}} -\dfrac{3}{\sqrt{2}}\\\\\\=-\ \dfrac{1}{\sqrt{2}}\\\\$

7 0

3 years ago

Which shows the expression below in simplified form? (7 × 10-3) - (2.3 × 10-6) A. 6.9977 × 10-3 B. 6.99977 × 10-3 C. 6.9977 × 10

rosijanka [135]

Option A

$(7 \times 10^{-3}) - (2.3 \times 10^{-6}) = 6.9977 \times 10^{-3}$

<em><u>Solution:</u></em>

Given expression is:

$(7 \times 10^{-3}) - (2.3 \times 10^{-6})$

To evaluate the expression, let us make the exponent of 10 same

$2.3 \times 10^{-6} = 0.0023 \times 10^{-6+3} = 0.0023 \times 10^{-3}$

[ Here, decimal point is moved three times left, so add 3 ]

Therefore,

$(7 \times 10^{-3}) - (2.3 \times 10^{-6}) = (7 \times 10^{-3}) - (0.0023 \times 10^{-3})$

$\text{Take the } 10^{-3} \text{ as common }$

$(7 \times 10^{-3}) - (0.0023 \times 10^{-3}) = 10^{-3}(7-0.0023)\\\\\text{ Solve for terms inside the bracket }\\\\(7 \times 10^{-3}) - (0.0023 \times 10^{-3}) = 10^{-3} \times 6.9977\\\\\text{Therefore, the simplified expression is: }\\\\(7 \times 10^{-3}) - (0.0023 \times 10^{-3}) = 6.9977 \times 10^{-3}$

Thus Option A is correct

6 0

4 years ago